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3 years ago

-3(2x-3)=-6+9 How do you solve?

2 answers:

5 0

You’re given:
-3(2x-3)= -6+9

you need to use distributive property and multiply -3 into 2x and -3:
-6x+9= -6+9

now you should simply the right side by adding 9 to -6:
-6x+9=3

then you need to subtract 9 from both sides in order to isolate the x term:
-6x= -6

then you divide both sides by -6 in order to get x by itself:
x=1

lakkis [162]3 years ago

4 0

Answer:

Step-by-step explanation:

do u have to like determine if its true or not or solve the question?

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a number is represented by 3XY6, where X and Y are unknown digits, wich of these is a true statement... A the place of the digit

Sophie [7]

D. The place of the digit 6 has a value that is 1/6 of the digit represented by y

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3 years ago

1. What is 3/5+3/5+3/5+3/5 equal to?

nydimaria [60]

Answer:

12/5 or 2 2/5

Step-by-step explanation:

3/5+3/5+3/5+3/5

=> (3+3+3+3) / 5

=> 12/5

=> 2 2/5

Hope it helps......

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3 years ago

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370 Girl and 450 Boys

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3 years ago

The area of two similar octagons are 4 m2 and 25 m2. What is the scale factor of their side lengths

mylen [45]

Answer:

The scale factor of the sides of the Octagon is 2:5

Step-by-step explanation:

Both these octagons can be considered as the combination of 8 similar triangles joined edge to edge.

We know this property of similar triangles, that the ratio of area of similar triangles is proportion to the square of the ratio of sides of the similar triangle.

$Side_{1} ^{2} : Side_{2} ^{2} =Area_{1} : Area _{2}$

From the above property, we plug in the values

$Side_{1} ^{2} : Side_{2} ^{2} =4: 25$

$Side_{1} : Side_{2} =2: 5$

Therefore, the ratio of the sides of the Octagon are 2:5.

7 0

3 years ago

Trapezoid EFGH is inscribed in a circle, with <img src="https://tex.z-dn.net/?f=EF%20%5Cparallel%20GH" id="TexFormula1" title="E

oksano4ka [1.4K]

Answer:

Arc EPF is 240°

Step-by-step explanation:

Since the quadrilateral, EFGH is a trapezoid and EF is parallel to GH, we have;

∠HGF + ∠GFE = 180°

∠GHE + ∠GFE = 180°

∠HGF + ∠HEF = 180°

∴∠HEF = ∠GFE

In ΔHEF and ΔGFE

∠EHF = ∠EGF (Angles subtending the same segment)

With side EF common to both triangles and ∠HEF = ∠GFE , we have;

ΔHEF ≅ ΔGFE (Angle Angle Side rule)

Hence, side FG = EH

For cyclic trapezoid side FG = EH

The base angles subtended by GH = 70

Arc EH = x² - 2·x

Arc FG = 56 - 3·x

Therefore;

70 + x² - 2·x + 56 - 3·x + arc EPF = 360 .............(1)

Also since the equation of a circle is (x-h)² + (y-k)² = r², where the center of the circle is (h, k), then as EF is a displacement of say z from GH, then arc EH = FG which gives;

x² - 2·x = 56 - 3·x

x² - 2·x - 56 + 3·x = 0

x² + x - 56 = 0

(x - 7)(x + 8) = 0

Therefore, since x > 0 we have x = 7

Plugging in the value of x into the equation (1), we have

70 + 7² - 2·7 + 56 - 3·7 + arc EPF = 360 .............(1)

70 + 70 + arc EPF = 360

arc EPF = 360 - 140 = 240°.

6 0

3 years ago