All categories

3 years ago

-3(2x-3)=-6+9 How do you solve?

2 answers:

5 0

You’re given:
-3(2x-3)= -6+9

you need to use distributive property and multiply -3 into 2x and -3:
-6x+9= -6+9

now you should simply the right side by adding 9 to -6:
-6x+9=3

then you need to subtract 9 from both sides in order to isolate the x term:
-6x= -6

then you divide both sides by -6 in order to get x by itself:
x=1

lakkis [162]3 years ago

4 0

Answer:

Step-by-step explanation:

do u have to like determine if its true or not or solve the question?

You might be interested in

Which of these triangles is not possible?

Firdavs [7]

Answer:

Step-by-step explanation:

5 0

2 years ago

Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle translates 2 units up and 1 unit right. Which rule repres

Nataly [62]

Answer:

The translation statement is given by:

$(x,y)\rightarrow (x+1,y+2)$

After the translation, the coordinates of vertex A is (-2,6).

Step-by-step explanation:

Given :

Vertices of a triangle ABC are:

A(−3, 4), B(4, −2), C(8, 3)

The triangle is translated 2 units up and 1 unit right.

To find the co-ordinates of point A after translation.

Translation rules.

For shift of $c$ units up, the translation is given as:

$(x,y)\rightarrow (x,y+c)$

For shift of $k$ units right, the translation is given as:

$(x,y)\rightarrow (x+k,y)$

So, it says the triangles is translated 2 units up and 1 unit right.

The translation statement is given by:

$(x,y)\rightarrow (x+1,y+2)$

So, co-ordinates of point A after translation is given by :

$(-3,4)\rightarrow (-3+1,4+2)=(-2,6)$

After the translation, the coordinates of vertex A is (-2,6).

4 0

3 years ago

(5 pts) A quadratic function f is given by f(x) = ax2 + bx + c where a is not 0. Select all

Vsevolod [243]

Answers:

a) True. Plug in x = 0 and it leads to y = c. Therefore, the point (0,c) is on the parabola.
b) False. Plug in y = 0 and apply the quadratic formula. One x intercept may sometimes be x = c, but it could easily be other values as well. Or perhaps you may not get any real number solutions at all. See part d) below.
c) True. If a < 0, then the leading coefficient is negative. Overall, both endpoints will tend toward negative infinity to produce a parabola that opens downward.
d) False. The quadratic may have one x intercept or it may not have any x intercepts at all. It depends on what the discriminant d = b^2 - 4ac is equal to. If d < 0, then we have no x intercepts. If d = 0, then we have exactly 1 x intercept. If d > 0, then we have two different x intercepts.
e) True. The vertex's x coordinate is -b/(2a). If b = 0, then the x coordinate of the vertex is 0. The vertical line x = 0 is directly on top of the y axis.

8 0

3 years ago

Show the working for <br><br> 3y^2 x 2y^5 x 5y^4 over 6y^3 x 4y^4

solong [7]

Answer:

please I can't do it I have not been thought

6 0

3 years ago

Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school

DochEvi [55]

Answer:

Step-by-step explanation:

We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).

p = 12/100 = 0.12

number of success, x = 20

n = 200

the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)

From the binomial probability calculator,

P(x ≥ 20) = 0.84

8 0

3 years ago