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zvonat [6]
3 years ago
12

8 hectograms = ____decagrams

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0
Hey Friend! :) Let's work this out!

1 gram = 10 decagrams
So, 8 hectograms = 80 decagrams

Hope this helps! (Don't forget Brainliest) :)
Tamiku [17]3 years ago
3 0
Recall that

hecto = 100
deca = 10

======

So,

8 hectograms
= 8 * (100 grams)
= 800 grams
= 80 * (10 grams)
= 80 decagrams <----- this is the answer.

I hope this helps! :-)
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Theres only 3 shapes that can form such regualr tessellations triangle square and regular hexagon so that being said triangle is your answer
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A fish tank holds 95 gallons of water and is losing water at a rate of 4 gallons per day. A second fish tank
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Answer: 95-4x<40+5x

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Water is being pumped into a conical tank that is 8 feet tall and has a diameter of 10 feet. If the water is being pumped in at
Deffense [45]

The rate of change of the depth of water in the tank when the tank is half

filled can be found using chain rule of differentiation.

When the tank is half filled, the depth of the water is changing at  <u>1.213 × </u>

<u>10⁻² ft.³/hour</u>.

Reasons:

The given parameter are;

Height of the conical tank, h = 8 feet

Diameter of the conical tank, d = 10 feet

Rate at which water is being pumped into the tank, = 3/5 ft.³/hr.

Required:

The rate at which the depth of the water in the tank is changing when the

tank is half full.

Solution:

The radius of the tank, r = d ÷ 2

∴ r = 10 ft. ÷ 2 = 5 ft.

Using similar triangles, we have;

\dfrac{r}{h} = \dfrac{5}{8}

The volume of the tank is therefore;

V = \mathbf{\dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h}

r = \dfrac{5}{8} \times h

Therefore;

V = \dfrac{1}{3} \cdot \pi \cdot \left(  \dfrac{5}{8} \times h\right)^2 \cdot h = \dfrac{25 \cdot h^3 \cdot \pi}{192}

By chain rule of differentiation, we have;

\dfrac{dV}{dt} = \mathbf{\dfrac{dV}{dh} \cdot \dfrac{dh}{dt}}

\dfrac{dV}{dh}=\dfrac{d}{h} \left(  \dfrac{25 \cdot h^3 \cdot \pi}{192} \right) = \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64}}

\dfrac{dV}{dt} = \dfrac{3}{5}  \ ft.^3/hour

Which gives;

\dfrac{3}{5} =  \mathbf{\dfrac{25 \cdot h^2 \cdot \pi}{64} \times \dfrac{dh}{dt}}

When the tank is half filled, we have;

V_{1/2} = \dfrac{1}{2} \times  \dfrac{1}{3} \times \pi \times 5^2 \times 8 =\mathbf{ \dfrac{25 \cdot h^3 \cdot \pi}{ 192}}

Solving gives;

h³ = 256

h = ∛256

\dfrac{3}{5} \times \dfrac{64}{25 \cdot h^2 \cdot \pi} = \dfrac{dh}{dt}

Which gives;

\dfrac{dh}{dt} = \dfrac{3}{5} \times \dfrac{64}{25 \cdot (\sqrt[3]{256}) ^2 \cdot \pi} \approx \mathbf{1.213\times 10^{-2}}

When the tank is half filled, the depth of the water is changing at  <u>1.213 × 10⁻² ft.³/hour</u>.

Learn more here:

brainly.com/question/9168560

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5 0
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Please help me if you can.​
dybincka [34]

Answer:

Step-by-step explanation:

<u>DEFINITIONS</u>

Standard Form: a way of expressing numbers that are too large or too small to be conveniently written in decimal form.

Monomial: a polynomial which has only one term.

Binomial: a polynomial that is the sum of two terms, each of which is a monomial.

<u>EXAMPLES</u>

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