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SCORPION-xisa [38]
2 years ago
15

4. Una fuerza le proporciona a la masa de 8 Kg. una aceleración de 2.2 m/s2. Calcular la magnitud de dicha fuerza en Newton.​

Mathematics
1 answer:
olganol [36]2 years ago
6 0

Answer:

4. Una fuerza le proporciona a la masa de 8 Kg. una aceleración de 2.2 m/s2. Calcular la magnitud de dicha fuerza en Newton.​   means

4. A force gives the 8 kg mass an acceleration of 2.2 m / s2. Calculate the magnitude of this force in Newton.

Step-by-step explanation:

hope this was helpful.

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Answer:

P(disease/positivetest) = 0.36116

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

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NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

P(B) >0

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

P(I)=0.025

P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975

P(PT/I)=0.904\\P(PT/NI)=0.041

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=0.904

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116

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Step-by-step explanation:

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