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omeli [17]
3 years ago
13

If 3x+7=x-1, then does x = -4?

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Hey there!!

To check whether x= -4, let's solve the equation.

Given:

3x+7 = x-1

Subtracting 2x on both sides:

2x + 7 = -1

Subtracting 7 on both sides:

2x = -1-7

2x = -8

Dividing 2 on both sides:

x = -8/2

x = -4

<u><em>Yes, x is -4. </em></u>

<u><em>Hope it helps!</em></u>

iragen [17]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

You multiply 3 by -4 to get -12, then add 7 to make the left side of the equation -5. On the right side, all you have to do is do -4 minus 1, which is -5. That being said, yes x=-4

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5 0
3 years ago
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
3 years ago
Read 2 more answers
The rectangle is divided into equal parts. what is the name of the equal parts
Tom [10]
Be more specific as in how many parts it is split into.
6 0
3 years ago
50 points + brainliest
victus00 [196]

Answer: D, D, D, D

Step-by-step explanation: Bro, it's literally all just D

7 0
3 years ago
Using Slopes of Parallel Lines Quick Check
Semenov [28]

Answer:

The answer is (B) ⇒ Yes. AB is parallel to CD and AD is parallel to BC

Step-by-step explanation:

<em>There is an important fact about the parallel lines: </em>

  • Parallel lines have equal slopes

<em>The rule of the slope of a line is:</em>

  • m=\frac{y_{2}-y_{1} }{x_{2}-x_{1}}, where (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line

<em>Let us use the fact and the rule to solve the question</em>

∵ ABCD is a quadrilateral

∵ A = (0, 2) , B = (2, 6), C = (9, 6), D = (7, 2)

∵ The opposite sides are AB, CD and AD, BC

Find the slopes of the four sides to check the parallel sides

∵ m_{AB}=\frac{6-2}{2-0}=\frac{4}{2}=2

∵ m_{CD}=\frac{2-6}{7-9}=\frac{-4}{-2}=2

∵ The slope of AB = The slope of CD

∴ AB // CD

∵ m_{AD}=\frac{2-2}{7-0}=\frac{0}{7}=0

∵ m_{BC}=\frac{6-6}{9-2}=\frac{0}{7}=0

∵ The slope of AB = The slope of CD

∴ AD // BC

The correct answer is:

Yes. AB is parallel to CD and AD is parallel to BC ⇒ (B)

5 0
3 years ago
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