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omeli [17]
2 years ago
13

If 3x+7=x-1, then does x = -4?

Mathematics
2 answers:
devlian [24]2 years ago
7 0

Hey there!!

To check whether x= -4, let's solve the equation.

Given:

3x+7 = x-1

Subtracting 2x on both sides:

2x + 7 = -1

Subtracting 7 on both sides:

2x = -1-7

2x = -8

Dividing 2 on both sides:

x = -8/2

x = -4

<u><em>Yes, x is -4. </em></u>

<u><em>Hope it helps!</em></u>

iragen [17]2 years ago
6 0

Answer:

Yes

Step-by-step explanation:

You multiply 3 by -4 to get -12, then add 7 to make the left side of the equation -5. On the right side, all you have to do is do -4 minus 1, which is -5. That being said, yes x=-4

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solve the following compound inequality graph the solution 7x = 35 ? please help and also show ur work on how u got it ​
erma4kov [3.2K]

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2 years ago
Which expression is equivalent to?
guapka [62]

Answer: \frac{2x\sqrt[4]{y^{2}}}{3}

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4 0
2 years ago
Please please help me. i’ll literally send you money. i need to pass please help
mihalych1998 [28]
<h3>Answer: Approximately 6.4 units</h3>

==================================================

Explanation:

The origin is the point (0,0)

Use the distance formula to find the distance from (0, 0) to (4, -5)

Let

(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\

be our two points. Plug those values into the distance formula below and use a calculator to compute

d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\

The distance between the two points (0,0) and (4,-5) is approximately 6.4 units.

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3 years ago
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