Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 100
μ = mean = 125
σ = standard deviation = 18
z-score = (100 – 125) / 18
z-score = (-25) / 18
z-score = -1.39
Find the probability that corresponds to the z-score in the z-table. (see attached images)
-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968
-0.09 : -0.1 = x - 0.0968 : -0.016
x - 0.0968 = -0.09(-0.016)/-0.1
x = -0.0144 + 0.0968
x = 0.0824
x = 0.0824
Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
Learn more about probability here: brainly.com/question/26822684
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Let the number be n. Then 2(n-10) = 6n + 14.
Multiplying out the left side, 2n - 20 = 6n + 14. Thus, -34=4n, and n = -17/2.
Answer:
g(a+1)=5a+2
Step-by-step explanation:
so (a+1) is the value of x
you can write it like this:
x=a+1
using substitution, we can swap out all 'x's for 'a+1's. like so;
g(a+1)=5(a+1)-3 -- given
=5a+5-3 -- distribute
=5a+2 -- simplify!
Hope i helped! have a great day! please mark brainliest!!
Answer:
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Step-by-step explanation:
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