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tatyana61 [14]
2 years ago
7

James purchases a property for $150,000 in 2015. In the first year of ownership the capital appreciation of the property (how mu

ch its value increases by per annum) is 4%. In year 2, the housing market suffers a crash and the house experiences a capital depreciation of 6%. Calculate the value of the property, to the nearest $1,000, at the end of year 2. Round your answer to the nearest $1,000.
Mathematics
1 answer:
Arisa [49]2 years ago
5 0

Answer:

$147,000

Step-by-step explanation:

<u>After 1st year:</u>

we need to increase 150,000 by 4%. That means the value would be 150,000 multiplied by 1.04. So:

150,000 * 1.04 = 156,000

<u>After 2nd year:</u>

The new appreciated value of 156,000 will now suffer a loss of  6%. So we need to find the new value by multiplying 156,000 by 0.94 (6% loss). So:

156,000 * 0.94 = 146,640

To the nearest 1000, this would be $147,000

You might be interested in
Give 1 pair of Vertical and 1 pair of Supplementary angles
mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0
1 year ago
~PLEASE HELP!~
Gwar [14]
I'm not sure, but what I got was -8.5, since it is only stating that it is -17 and 5, and you need to figure out Point B, when it is between A and 0. So, you don't pay attention to 1-5. You only want -17 through 0. -17 divided by two would be -8.5
5 0
3 years ago
Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work.
andrey2020 [161]
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5 0
3 years ago
HElP ME!!!!!!! PLS!!!!
ra1l [238]

Answer:

Each bag will get 5 candy canes and 3 cookies.

Step-by-step explanation:

Find the divisors of both numbers

75 = 1,75 : 3,25 : 5,15 : 15,5 : 25,3 : 75,1

45 = 1,45 : 3,15 : 5,9 : 9,5 : 15,3 : 45,1

Since the largest common divisor is 15, we want to use 15.

Each bag will get 5 candy canes and 3 cookies.

4 0
2 years ago
Question 2 of 5
AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is f(n)=f(n-1)+d, f(1)=a,n\geq 2 and the explicit formula is f(n)=a+(n-1)d, where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is f(n)=rf(n-1), f(1)=a,n\geq 2 and the explicit formula is f(n)=ar^{n-1}, where a is the first term and r is the common ratio.

The first recursive formula is:

f(1)=5

f(n)=f(n-1)+5 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(5)

f(n)=5+5(n-1)

Therefore, the correct option is A, i.e., f(n)=5+5(n-1).

The second recursive formula is:

f(1)=5

f(n)=3f(n-1) for n\geq 2.

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

f(n)=5(3)^{n-1}

Therefore, the correct option is F, i.e., f(n)=5(3)^{n-1}.

The third recursive formula is:

f(1)=5

f(n)=f(n-1)+3 for n\geq 2.

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

f(n)=5+(n-1)(3)

f(n)=5+3(n-1)

Therefore, the correct option is D, i.e., f(n)=5+3(n-1).

6 0
3 years ago
Read 2 more answers
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