Additive relationships mean you add the SAME number to any x-value to get the corresponding y-value. If it's not the same number every time, it is NOT an additive relationship. Subtraction can be an additive relationship because subtracting a number is the same as adding a negative number (example: 5 - 2 = 5 + (-2)).
Answer:
x = 3/2 or x = -5/4
Step-by-step explanation:
Solve for x over the real numbers:
8 x^2 - 2 x - 15 = 0
Using the quadratic formula, solve for x.
x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:
x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16
Simplify radicals.
sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:
x = (2 + 22)/16 or x = (2 - 22)/16
Evaluate (2 + 22)/16.
(2 + 22)/16 = 24/16 = 3/2:
x = 3/2 or x = (2 - 22)/16
Evaluate (2 - 22)/16.
(2 - 22)/16 = -20/16 = -5/4:
Answer: x = 3/2 or x = -5/4
Answer:
A ∩ B = {4, 6}
Step-by-step explanation:
A die had 6 faces
S = {1, 2, 3, 4, 5, 6}
If A be the event of rolling an even number, then;
A = {2, 4, 6}
If B be the event of rolling a number greater than 3, then;
B = {4, 5, 6}
A ∩ B are the values that are common to both sets
A ∩ B = {4, 6}
Answer:
10/81
Step-by-step explanation:
let,
y=kx
y=10 when x=9
so,
10=k×9
or, k=10/9
when x=1/9
y=kx
or, y=(10/9)×(1/9)
or, y=10/81
