Y = x + 1
y = 2x - 1
basically we r going to sub in one y for another
x + 1 = 2x - 1
1 + 1 = 2x - x
2 = x
now we sub 2 in for x in either of the original equations to find y
y = x + 1
y = 2 + 1
y = 3
so ur solution is (2,3)
4p+9-7p+2=
group like terms
4p-7p+9+2
addd like terms
-3p+11
that is simplified form
Answer:
The length of the rectangular playing field is 84 yards and the width is 44 yards
Step-by-step explanation:
Let
x ------> the length of the rectangular playing field
y -----> the width of the rectangular playing field
we know that
The perimeter of the rectangular playing field is equal to


so
------> equation A
we have that
-----> equation B
Solve the system by substitution
Substitute equation B in equation A and solve for y





Find the value of x

therefore
The length of the rectangular playing field is 84 yards and the width is 44 yards
To find the area of the triangle, you use the formula A=bh/2. This gives you the area of 49in^2 for the triangle, eliminating choices C and D. The area of the entire square is 14^2, or 196in^2, which gives us 4 when divided by the area of the triangle, 49in^2. Therefore, the answer is B, or that the area of the triangle is 49in^2 so she can create only 4 triangles.