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3 years ago

It's the 2nd question I know how it is done ....sum and product method but the root is confusing me can any one explain me plz

Mathematics

1 answer:

weeeeeb [17]3 years ago

8 0

Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)

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Find the area pls- i need help

Tresset [83]

Answer:

1. 36 sq un

2. 40 sq un

3. 20 sq un

Step-by-step explanation:

The answer for number one is 36 square units because the rectangular area is 24 sq un and the triangular area is 12 sq un so I added them to get 36 sq un. The second answer is 40 sq un because if you cut the shape into 2 shapes you get 2 equal trapezoids. Each trapezoid is 20 sq un so I multiplied it by two to get 40 sq un. The third answer is 20 because the side triangles are 2 sq un each and the square on the bottom is 16 sq un. By the way, sq un means square units lol.

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3 years ago

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In a Science class students made rockets out of empty 2-liter bottles. When launched, Karen's rocket reached a height of 12 and

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13 9/10

This is just a math equation. Just add 12 1/2 to 1 2/5 and remember that the bottoms of fractions have to be the same and if you change the bottoms, you have to change the top just as much :)

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3 years ago

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Which equation represents the line that passes through points (0, 6) and (2, 0)?

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equation
y = -3x + 6

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3 years ago

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What is constant of Proportionality in the equation y = 2.5x

Natasha_Volkova [10]

Answer:

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Compare y = 2.5x to y = kx (which is the equation for direct proportion):

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Suppose that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the pop

pav-90 [236]

Answer:

A 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

Step-by-step explanation:

Since in the question only 9 random scores are given, so I am performing the calculation using 9 random scores.

We are given that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6.

The accompanying data set of 9 random scores in ascending order is given as; 75, 86, 86, 88, 89, 93, 93, 98, 107

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean score = $\frac{\sum X}{n}$ = $\frac{815}{9}$ = 90.56

$\sigma$ = population standard deviation = 6

n = sample of random scores = 9

$\mu$ = population mean score for all bowlers

Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $90.56-1.96 \times {\frac{6}{\sqrt{9} } }$ , $90.56+1.96 \times {\frac{6}{\sqrt{9} } }$ ]

= [86.64 , 94.48]

Therefore, a 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].

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3 years ago