It should be 34/5*. If you create an improper fraction out of the original one, then creating the reciprocal will be easier.
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
A pair of perpendicular lines would be line CF and line AJ.
Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
The value of x is 2 and the length of JK is 4
<h3>How to solve the unknown variables?</h3>
The given parameters from the circle are:
- Center = Point S
- Segment JK = 8
- Segment LK = 2x + 4
- Congruent SN = SP = 7
The lines SR and SQ are the radii of the circle P
This means that lines JK and JL are congruent
So, we have:
JK = KL
Substitute LK = 2x + 4 and JK = 4
4 = 2x + 4
Rewrite the above equation as:
2x + 4 = 8
Subtract 4 from both sides
2x + 4 - 4 = 8 - 4
Evaluate the difference
2x = 4
Divide both sides by 2
2x = 4/2
This gives
x = 2
Substitute x = 2 in LK = 2x + 4
LK = 2*2 + 4
Evaluate the product of 2 and 2
LK = 4 + 4
This gives
LK = 8
The point N divides JK into 2 equal segments
So, we have
JN = JK/2
JN= 8/2
JN = 4
Hence, the value of x is 2 and the length of JK is 4
Read more about circles at:
brainly.com/question/11833983
#SPJ1
Answer:
∠DAB = ∠DBA
Then AD=DB from above statement