Answer:
-2 a b + 2 b + 6 a^2 + 9
Step-by-step explanation:
Simplify the following:
2 a^2 + a b + 2 b + 4 a^2 - 3 a b + 9
Grouping like terms, 2 a^2 + a b + 2 b + 4 a^2 - 3 a b + 9 = (a b - 3 a b) + 2 b + (2 a^2 + 4 a^2) + 9:
(a b - 3 a b) + 2 b + (2 a^2 + 4 a^2) + 9
a b + a b (-3) = -2 a b:
-2 a b + 2 b + (2 a^2 + 4 a^2) + 9
2 a^2 + 4 a^2 = 6 a^2:
Answer: -2 a b + 2 b + 6 a^2 + 9
Four hundred-thousand plus sixty-thousand plus five-thousand plus one-hundred.
Pls provide the complete question.
Let the three consecutive number be x,x+1 and x+2.
It is given sum of three consecutive numbers is 46.
So,x+x+1+x+2=46
3x+3=46.
Subtracting 3 both sides
3x=46-3
3x=43.
x= 
Since is not an integer there is no true answer to this problem.
