the equation of line passing through given point parallel to y = -2x+7 is: ![y = -2x+9](https://tex.z-dn.net/?f=y%20%3D%20-2x%2B9)
Step-by-step explanation:
Given equation of line is:
![y = -2x+7](https://tex.z-dn.net/?f=y%20%3D%20-2x%2B7)
As the given line is in slope intercept form, the coefficient of x is the slope
Let m1 be the slope of given line
![m_1 = -2](https://tex.z-dn.net/?f=m_1%20%3D%20-2)
Let m2 be the slope of second line then
![m_2= -2](https://tex.z-dn.net/?f=m_2%3D%20-2)
The equation of line is given by:
![y= m_2x+b](https://tex.z-dn.net/?f=y%3D%20m_2x%2Bb)
Putting the value of slope
![y = -2x+b](https://tex.z-dn.net/?f=y%20%3D%20-2x%2Bb)
Putting the point (4,1) in the equation
![y = -2x+b\\1 = -2(4)+b\\1= -8+b\\b = 1+8\\b = 9](https://tex.z-dn.net/?f=y%20%3D%20-2x%2Bb%5C%5C1%20%3D%20-2%284%29%2Bb%5C%5C1%3D%20-8%2Bb%5C%5Cb%20%3D%201%2B8%5C%5Cb%20%3D%209)
Putting the value of b in the equation
![y = -2x+9](https://tex.z-dn.net/?f=y%20%3D%20-2x%2B9)
Hence,
the equation of line passing through given point parallel to y = -2x+7 is: ![y = -2x+9](https://tex.z-dn.net/?f=y%20%3D%20-2x%2B9)
Keywords: Slope, intercepts
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