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just olya [345]
3 years ago
10

Plzz help

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
5 0

1/2 * (n+4) = (5n) - 3

B. when you say it out loud and write it as it sounds you will most likely get the right answer

:)))

dybincka [34]3 years ago
4 0

D, is the final answer!!! :)

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Help please. See photo
olganol [36]

\huge\sf\purple{}

Option B

6 0
2 years ago
Read 2 more answers
A gate is made up of a rectangle and has a height of 6ft find the area of the gate
Snezhnost [94]

Answer: The area is 18ft

6 0
3 years ago
Oakley charged $795 to his credit card last month. What is the first minimum payment he must make? (2 points)$25.00
DaniilM [7]

Answer:

$31.80

Step-by-step explanation:

<u><em>The complete question is</em></u>

Use the details of Oakley's new credit card to answer the question that follows. APR 11.9% compounded monthly Grace Period 28 days Minimum Payment 4% of the remaining balance or $25, whichever is higher Oakley charged $795 to his credit card last month. What is the first minimum payment he must make?

step 1

Find out the 4% of the balance of $795

0.04(795)=\$31.80

so

\$31.80 >\$25

This amount is higher than $25,

therefore

The first minimum payment he must make is $31.80

4 0
2 years ago
Both answers plssss ?????!?
Troyanec [42]

Answer:

4) C

5) C

Step-by-step explanation:

7 0
3 years ago
A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
3 years ago
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