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2 years ago

What is the probability that the wine cooler would be less than 45 degrees

Mathematics

1 answer:

katrin [286]2 years ago

4 0

Idk
At least 20 characters to explain it well.

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PLEASE HELP ASAP For each expression below, select the letter that corresponds to the equivalent expression from the given list.

LenaWriter [7]

BAnswer:

B-D-A

Step-by-step explanation:

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2 years ago

What is the circumference of a circle with a radius of 5.4 inches? Enter your answer as a decimal in the box. Use 3.14 for pi. R

LenKa [72]

Hi there! The formula for circumference is π * diameter. Diameter is the length across the circle and twice the length of the radius.The radius is 5.4, so we will multiply that by 2 to get 10.8. The diameter is 10.8 inches. Now, multiply that numebr by 3.14 to find the circumference. 10.8 * 3.14 is 33.912 or 33.9 when rounded to the nearest tenth. There. The circumference is approx. 33.9 inches.

7 0

2 years ago

Read 2 more answers

What’s the answer to this?

Vanyuwa [196]

Answer:

answer c

Step-by-step explanation:

the two x-intercepts are (-4,0) and (2,0) so the factors of the equation are (x-2) and (x+4). if you multiply the factors it gives you the equation of the graph whic is x^2+2x-8 so c= -8 and b= 2

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2 years ago

What is the slope of a line that passes through the points (–3, 2) and (–6, 5)?

lilavasa [31]

Answer:

-1

Step-by-step explanation:

just do y2-y1 over x2-x1.

8 0

2 years ago

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$

So, the value of the function is minimum at $r=1.05$

$h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12$

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3$

The minimum surface area is $20.91\ \text{ft}^3$ .

8 0

2 years ago