12.5663706144 or yes, 12.57
The answer is 2 x 10^4 or 2 to the power of 4 (4th power) where;
2 x 10 x 10 x 10 x 10
2 x 10 =20
20 x 10= 200
200 x 10 = 2000
2000 x 10 = 20 000
Expressing a number to a single digit integer times a power of 10 is also writing a number in scientific form,where the number is multiplied by 10 to nth "power". Scientific notation is also called standard index form whereby, too large or too big numbers.
In writing the scientific notation of a number it follows this form: m x 10^n ( m is multiplied to 10 to the power of n) where, m, the coefficient, is the real number and n is the exponent integer.<span><span /></span>
7^5/4 would be the answer to the question I think you are asking
They're not equivalent.
(vertical bars) represents the absolute value of x. How it works is that it turns negative numbers positive but leaves 0 and positive numbers alone (hence it gets a number's distance from 0 on the number line).
(square brackets) usually represents the floor function, which returns the largest integer that is less than or equal to x. (The floor of x can also be written as
--- it depends on what your textbook/source says).
To solve
, you first transform it into the equivalent equation
. Then by definition of absolute value, there are only two solutions for the first equation: x = 10 or x = -10.
[x] = 10 has infinitely many solutions. For example, the floor of 10 is 10, so
, thus a solution for the second equation is x = 10
The floor of 10.1 is 10, so
, thus another solution for the second equation is x = 10.1.
The two equations do not have the same solution set (as x = 10.1 does not solve |x| - 3 = 7 but solves [x] = 10), so they're not equivalent.
Answer:
(5,1)
Step-by-step explanation:
Given :

Solution :
Equation 1 : y=x-4
Equation 2 : y = -x+6
We will use substitution method
Putting the value of y from equation 1 in equation 2
⇒
⇒
⇒
⇒
⇒
Now substituting value of x in equation 1 to get value of y
⇒
⇒
⇒
Thus the solution of given system of equations is (5,1)
We have also solved it by graphing the equations
You can refer the attached figure.