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3 years ago

I have a math problem does anyone know what is. 18 is 50% of____

Mathematics

2 answers:

schepotkina [342]3 years ago

6 0

The answer is 36 because 50% is half 18 times 2 is 36.

ohaa [14]3 years ago

3 0

Remember: 50% means 1/2. So, if 18 is 50%, or 1/2, of a number, the number must be double 18.

18 x 2 = 36

18 is 50% of 36.

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I need help with #8 and #9 Please! :)<br> I will mark as brainliest!

k0ka [10]

Answer:

see explanation

Step-by-step explanation:

(8)

the common ratio r, of a geometric sequence is

r = $\frac{a_{2} }{a_{1} }$ = $\frac{a_{3} }{a_{2} }$ = ......

r = $\frac{\frac{1}{32} }{\frac{1}{256} }$ = $\frac{\frac{1}{4} }{\frac{1}{32} }$ = 8

(9)

The simplest way to evaluate the sum is to substitute k = 3, 4, 5, 6 into each term and sum them

(- 9 + 20) + (- 12 + 20) + (- 15 + 20) + (- 18 + 20)

= 11 + 8 + 5 + 2 = 26

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3 years ago

Find the prime factorization of 210.

Xelga [282]

5 x 2 x 7 x 3
Hope it helped! :)

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3 years ago

Read 2 more answers

What single decimal multiplier would you use to increase by 7% followed by a 4% decrease?

Nostrana [21]

Answer: To increase an amount by 7%, you would want to use 1.07 as the multiplier. To decrease it, you would use 0.93

Step-by-step explanation:

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3 years ago

A kangaroo hops 2 kilometers in 3 minutes. At this rate, how far does the kangaroo travel in 2 minutes? *

Dmitrij [34]

Answer:

At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.

Step-by-step explanation:

If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:

2 km / 3 min = 0.666 km per minute (2/3 x 2)

0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)

Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.

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3 years ago

Find the dot product of the position vectors whose terminal points are (14, 9) and (3, 6).

erma4kov [3.2K]

Answer:

Step-by-step explanation:

The formula for the dot product of vectors is

u·v = |u||v|cosθ

where |u| and |v| are the magnitudes (lengths) of the vectors. The formula for that is the same as Pythagorean's Theorem.

$|u|=\sqrt{14^2+9^2}$ which is $\sqrt{277}$

$|v|=\sqrt{3^2+6^2}$ which is $\sqrt{45}$

I am assuming by looking at the above that you can determine where the numbers under the square root signs came from. It's pretty apparent.

We also need the angle, which of course has its own formula.

$cos\theta=\frac{uv}{|u||v|}$ where uv has ITS own formula:

uv = (14 * 3) + (9 * 6) which is taking the numbers in the i positions in the first set of parenthesis and adding their product to the product of the numbers in the j positions.

uv = 96.

To get the denominator, multiply the lengths of the vectors together. Then take the inverse cosine of the whole mess:

$cos^{-1}\theta=\frac{96}{111.64676}$ which returns an angle measure of 30.7. Plugging that all into the dot product formula:

$u*v=\sqrt{277}*\sqrt{45}cos(30.7)$ gives you a dot product of 96

6 0

3 years ago