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sweet-ann [11.9K]
3 years ago
8

If 3 cars can hold 15 people how many cars are needed for 165. People. There is no pictures

Mathematics
2 answers:
Paha777 [63]3 years ago
7 0
3 cars hold 15 people so...
1 car holds 5 people.

Therefore...

33 cars hold 165 people.

inn [45]3 years ago
4 0
To solve this problem, we can divide 165 people by 15 to start to find out how many cars there will be for 165 people. This is because this is a proportion. 165 divided by 15 is 11. Since 165:15 = 11, that means that C:3 = 11 too (with C being the number of cars for 165 people). If C:3 = 11, we can multiply each side by 3 to figure out the C is equal to 33 (we multiply by 3 to get rid of the denominator, since the : sign means to divide). That means that 33 cars will be needed for 165 people. 
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The table shows the values of a function f(x).
QveST [7]

Answer:

The average rate of change is =-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

=\frac{f(b)-f(a)}{b-a}

We want to find the average rate of change of the function represented in the table  from x=-2 to x=2.

=\frac{f(2)-f(-2)}{2--2}

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

=\frac{9-25}{2--2}

=\frac{-16}{4}

=-4

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3 years ago
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koban [17]

Answer:

62.5

Step-by-step explanation:

P = (6.50f) - 100

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P = (6.50*25) - 100

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2 years ago
A simple modeling clay recipe
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Read 2 more answers
A stereo store is offering a special price on a complete set of components (receiver, compact disc player, speakers, turntable).
Juli2301 [7.4K]

Answer:

a) 240 ways

b) 12 ways

c) 108 ways

d) 132 ways

e) i) 0.55

ii) 0.4125

Step-by-step explanation:

Given the components:

Receiver, compound disk player, speakers, turntable.

Then a purcahser is offered a choice of manufacturer for each component:

Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood => 5 offers

Compact disc player: Onkyo, Pioneer, Sony, Technics => 4 offers

Speakers: Boston, Infinity, Polk => 3 offers

Turntable: Onkyo, Sony, Teac, Technics => 4 offers

a) The number of ways one component of each type can be selected =

\left(\begin{array}{ccc}5\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right)

= 5 * 4 * 3 * 4  = 240 ways

b) If both the receiver and compact disk are to be sony.

In the receiver, the purchaser was offered 1 Sony, also in the CD(compact disk) player the purchaser was offered 1 Sony.

Thus, the number of ways components can be selected if both receiver and player are to be Sony is:

\left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right)

= 1 * 1 * 3 * 4 = 12 ways

c) If none is to be Sony.

Let's exclude Sony from each component.

Receiver has 1 sony = 5 - 1 = 4

CD player has 1 Sony = 4 - 1 = 3

Speakers had 0 sony = 3 - 0 = 3

Turntable has 1 sony = 4 - 1 = 3

Therefore, the number of ways can be selected if none is to be sony:

\left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right)

= 4 * 3 * 3 * 3 = 108 ways

d) If at least one sony is to be included.

Number of ways can a selection be made if at least one Sony component is to be included =

Total possible selections - possible selections without Sony

= 240 - 108

= 132 ways

e) If someone flips switches on the selection in a completely random fashion.

i) Probability of selecting at least one Sony component=

Possible selections with at least one sony / Total number of possible selections

\frac{132}{240} = 0.55

ii) Probability of selecting exactly one sony component =

Possible selections with exactly one sony / Total number of possible selections.

\frac{\left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right)}{240}

= \frac{(1*3*3*3)+(4*1*3*3)+(4*3*3*1)}{240}

\frac{27 + 36 + 36}{240} = \frac{99}{240} = 0.4125

5 0
3 years ago
What is the domain and range​
kogti [31]

Answer:

The domain is all the x-values, and the range is all the y-values

Step-by-step explanation:

7 0
3 years ago
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