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Neporo4naja [7]
4 years ago
5

During track practice,Jonathan ran 5kilometers.Rod ran 4,250 meters.Who ran further?Explain

Mathematics
1 answer:
svp [43]4 years ago
3 0

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Please list how long it takes for each person to pack a shelf alone
vaieri [72.5K]

It takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

<h3>What is Rate and Ratio ?</h3>

A ratio can sometimes be regarded as fraction. While rate has something to do with time.

Given that Jay and Kay can pack the shelves in one aisle of the supermarket in 30 minutes. Kay and Elle take 35 minutes to do the same job. When Jay and Elle work together, the job takes 42 minutes.

Let

  • J = Jay
  • K = Kay
  • E = Elle

The interpretation of the question go thus;

1/J + 1/K = 1/30 ........ (1)

1/K + 1/E = 1/35 .........(2)

1/J + 1/E = 1/42 .........(3)

Make 1/J and 1/E the subject of formula in equation 1 and 2 respectively and substitute them in equation 3

1/J = 1/30 - 1/K  ........ (4)

1/E = 1/35 - 1/K  .........(5)

1/30 - 1/K + 1/35 - 1/K = 1/42

Collect the like terms

- 1/K - 1/K = 1/42 - 1/30 - 1/35

-2/K = (35 - 49 - 42)/1470

-2/K = -56/1470

1/K = 28/1470

Reciprocate both sides

K = 1470/28

K = 52.5 minutes.

Substitute K in both equation 4 and 5

1/J = 1/30 - 28/1470

1/J = (49 - 28)/1470

1/J = 21/1470

Reciprocate both sides

J = 1470/21

J = 70 minutes

1/E = 1/35 - 28/1470

1/E = (42 - 28)/1470

1/E = 14/1470

Reciprocate both sides

E = 1470/14

E = 105 minutes

Therefore, it takes Jay, Elle and Kay to work individually for 70 minutes, 105 minutes and 52.5 minutes respectively

Learn more about Rate here: brainly.com/question/8728504

#SPJ1

7 0
2 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

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