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2 years ago

7

Tim answered all the questions on his math test but got 10 answers wrong. He received 4 points for every correct answer, and the

re was no penalty for wrong answers. His score was 76 points.

1 answer:

Wewaii [24]2 years ago

8 0

What's the question in this it just says stuff about Tim

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Given: Quadrilateral ABCD is a parallelogram with diagonals AC and BD intersecting at E. Prove: Triangle AED is congruent to Tri

daser333 [38]

Answer:

Step-by-step explanation:

In ΔAED , ΔCEB

AD = BC { opposite sides of parallelogram are equal}

AE = CE { diagonals of parallelogram bisects each other}

BE = DE { diagonals of parallelogram bisects each other}

ΔAED ≅ ΔCEB (SSS congruence)

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2 years ago

What is the diameter of a circle with a Circumference of 17.21? *

kkurt [141]

Answer:

5.478113141

Step-by-step explanation:

to find diameter when you have the circumference you use the formula d= $\frac{c}{pi}$ , so you divide the circumference by π and you get diameter, round your answer if you're asked to.

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2 years ago

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Find the 2 points of intersection <br><br> 14 points!!!

goblinko [34]

Answer:

Here is the graph for it.

Step-by-step explanation:

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2 years ago

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What are the graphs of y = sin x and y = csc x in the interval from -2pi to 2pi?

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The graphs are attached.

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3 years ago

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What two numbers can add to 4 but multiple to -12

olasank [31]

Answer:

<em>Numbers: 6 and -2</em>

Step-by-step explanation:

<u>Equations</u>

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

$x+y=4\qquad\qquad [1]$

$x.y=-12\qquad\qquad [2]$

Solving [1] for y:

$y=4-x$

Substituting in [2]

$x(4-x)=-12$

Operating:

$4x-x^2=-12$

Rearranging:

$x^2-4x-12=0$

Solving with the quadratic formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

With a=1, b=-4, c=-12:

$\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}$

$\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}$

$\displaystyle x=\frac{4\pm 8}{2}$

The solutions are:

$\displaystyle x=\frac{4+ 8}{2}=6$

$\displaystyle x=\frac{4- 8}{2}=-2$

This confirms the preliminary results.

Numbers: 6 and -2

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2 years ago