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matrenka [14]
3 years ago
5

It's B right? please help will mark brainliest

Mathematics
1 answer:
Strike441 [17]3 years ago
6 0

Product         Function              Year 1   Year 2   Year 3

Product 1          f(x) = x³                 1            8          27

Product 2         g(x) = x² + 11      12         15          20

Product 3         h(x) = 4^x              4         16          64

Product 4          j(x) = 4x + 8        12        16           20


Product 3 exceeds the prices of other products. x is an exponent of 4, thus, the price increase is exponential.


Hope this helps :)



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pshichka [43]

Answer: A! x=-1 2/5, y= 1 3/5

Step-by-step explanation:

First put -3x+3y=9 into slope-intercept form(y=mx+b)

3y=-3x+9

then solve for y

y=-1x+3

enter your y-intercept into the equation below..

2x-7(-1x+3)=-14

2x+7x-21=-14

2x+7x=-14+21(when changing sides it changes signs that's why 21 is now a positive)

2x-7x=7

-5x=7 divide -5 into 7

7/5

x=-1 and 2/5

then input x back into the first equation

-3(7/-5)+3y=9

21/5+3y=9

3y=9-21/5

3y=24/5

divide 3 into 24/5

=24/15=1 and 9/15 reduce it anddd

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7 0
3 years ago
Determine whether this situation represents independent or dependent events. "Three green jelly bean, five red jelly beans and t
igor_vitrenko [27]

Answer:

Independent Events

Step-by-step explanation:

Given

Green = 3\\ Orange = 2\\ Red = 5

Required

Dependent or independent event

The probability of selecting a green jelly remains unchanged before and after selecting the first orange jelly.

<u>Before selecting the orange jelly:</u>

P(Green) = \frac{Green}{Total}

P(Green) = \frac{3}{10}

<u>After selecting the orange jelly:</u>

P(Green) = \frac{Green}{Total}

P(Green) = \frac{3}{10}

Because the probabilities remain unchanged, the selection of a green jelly is independent of the selection of the first orange jelly.

5 0
3 years ago
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mezya [45]

Answer:

1/2

Step-by-step explanation:

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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A = pi r^2

A = pi 6^2

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A shaded = 64 pi - 36 pi

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7 0
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