Answer : The energy removed must be, -34.67 kJ
Solution :
The process involved in this problem are :
The expression used will be:
where,
= heat available for the reaction =
m = mass of benzene = 125 g
= specific heat of solid benzene =
= specific heat of liquid benzene =
= enthalpy change for fusion =
Molar mass of benzene = 78 g/mole
Now put all the given values in the above expression, we get:
Therefore, the energy removed must be, -34.67 kJ