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alukav5142 [94]
3 years ago
8

Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form so

lid NiS and aqueous NaCl. If no reaction occurs, simply write only NR.
Chemistry
1 answer:
Reptile [31]3 years ago
3 0

Answer:

Explanation:

The chemical reaction of the well-balanced equation is as follows:

\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}

The aforementioned reaction's ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}

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Chemical equation:

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. A 500.0 mL buffer solution contains 0.30 M acetic acid (CH3COOH) and 0.20 M sodium acetate (CH3COONa). What will the pH of thi
julia-pushkina [17]

Answer:

pH = 4.57

Explanation:

pH = pKa + log ([OAc⁺]/[HOAc])

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Read 2 more answers
2 Fe2S3 +902 - 2 Fe2O3 + 6 SO2
maksim [4K]

Answer:

3.93 mol

Explanation:

The balanced equation is given as;

2 Fe₂S₃+ 9 O₂ --> 2 Fe₂O₃ + 6 SO₂

From the reaction;

2 mol of Fe₂S₃ reacts with 9 mol of O₂ to form 6 mol of 6 SO₂

This means;

1 mol of Fe₂S₃  requires 9/2 mol of O₂

Also,

1 mol of O₂ requires 1/9 mol of Fe₂S₃

In the question, we have;

1.31 moles of Fe2S3 and 22.8 moles of O2

The limiting reactant which determine how much of the product formed is; Fe₂S₃ because O₂ is in excess.

The relationship between Fe₂S₃ and SO₂ is;

2 mol Fe₂S₃ produces 6 mol of SO₂

1.31 mol of Fe₂S₃ would produce x mol ?

2 = 6

1.31 = x

x = 6 * 1.31 / 2 = 3.93 mol

8 0
3 years ago
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