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3 years ago

Compare and contrast an earthquake and a tsunami. Include one way they are similar and two ways they are different.

2 answers:

7 0

One way they are the same is, they both disrupt the biosphere weather breaking or any other thing. Two ways they are different is earth quakes usually happen because a plate has moved or is moving. A tsunami has to do with water being drawn back creating a big tidal wave. Another difference is, an earthquake happens very sudden, you can't predict when they are coming. A tsunami you can predict because of the weather that has been happening lately in that area.

Sorry for the long answer, but hope this helped. :)

Anon25 [30]3 years ago

6 0

One way they are similar is because an earthquake causes a tsunami so they are connected. two ways they are not is because ones dealing with water and ones dealing with land, and an earthquake is very sudden while a tsunami, you know its coming and you have time to move.

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A student calculates the mass of a piece of copper to be 8.3 grams. The actual mass of the copper is 10. grams. What is the perc

jok3333 [9.3K]

<u>Answer:</u>

17%

<u>Explanation:</u>

Mass of a piece of copper calculated by student = 8.3 grams

Actual mass of copper = 10 grams

We know the formula for the percent error:

Percentage error = (| experimental value - actual value | / actual value) * 100

So substituting the given values in the above formula:

Percent error = (|8.3 - 10| / 10) * 100 = (1.7/10) * 100 = 17%

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4 years ago

Calcium has a cubic closest packed structure (fcc) as a solid. Assuming that calcium has an atomic radius of 197 pm, calculate t

Paha777 [63]

Answer:

$1.536 g/cm^3$ is the density of solid calcium.

Explanation:

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

We have:

r = 197 pm = $197\times 10^{-12} m = 197\times 10^{-12}\times 100 cm$

$r=197\times 10^{-10} m$

$a=r\times 2\sqrt{2}$

$a=197\times 10^{-10} m\times 2\sqrt{2}=557.200\times 10^{-10} cm$

M = 40 g/mol

Z = 4

On substituting all the given values , we will get the value of 'a'.

$\rho =\frac{4\times 40 g/mol}{6.022\times 10^{23} mol^{-1}\times (557.200\times 10^{-10} cm)^{3}}$

$\rho =1.536 g/cm^3$

$1.536 g/cm^3$ is the density of solid calcium.

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3 years ago

**EASY**

Svetach [21]

Answer: But because part 2 stays the same

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3 years ago

Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of Pb(NO3)2 are heat

Dmitry_Shevchenko [17]

2Pb(NO₃)₂ = 2PbO + 4NO₂ + O₂

m{Pb(NO₃)₂}=9.9 g
m'{PbO}=5.5 g
M{Pb(NO₃)₂}=331.2 g/mol
M{PbO}=223.2 g/mol
w-?

w=m'{PbO}/m{PbO}

m{PbO}=M{PbO}m{Pb(NO₃)₂}/M{Pb(NO₃)₂}

w=m'{PbO}M{Pb(NO₃)₂}/[M{PbO}m{Pb(NO₃)₂}]

w=5.5*331.2/[223.2*9.9]=0.8244 (82.44%)

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