Answer:
C 200
Step-by-step explanation:
It does not appear to be LINEAR so
Start with :
pulse rate = y = 73e^kx
sub in x = .7 when y = 155
155 = 73 e^(.7 * k)
ln ( 155/73) = .7k
.75296567 = .7k
k = 1.07567
for x = 0.9 :
pulse rate = y = 73 e^(1.07567 * .9) = ~ 192 so I expect answer is 200
Answer:
Step-by-step explanation:
Using the formula for finding the circumference of a circle.
C = 2πr
r is the radius
radius = diameter/2
radius = 10/2
radius = 5in
C ,= 2(3.14)(5)
C = 20(3.14)
C = 31.4×2
C = 62.8in (for 1 rotation)
For 16 rotations;
C = 16×62.8
C = 1004.8in
The distance covered is 1004.8in
We know that
[scale factor] is equal to the ratio <span>between the lengths of their edges
so
scale factor=2/5
volume smaller cylinder/volume larger cylinder=[scale factor]</span>³
volume smaller cylinder/volume larger cylinder=[2/5]³---> 8/125
the answer is
8/125
For this case we have the following equation:
y = 3t + 6
Where we have the following variables:
t: time in minutes
y: distance traveled
We have then that the slope of the line is equal to 3.
The slope of the line represents the speed in feet per minute of the ant.
The speed of the ant is 3 feet per minute.
Answer:
C. The ant is crawling at 3 feet per minute