I saw the figure of the fishpond. It composed of a rectangle and a circle. The circle is cut into two and each half is attached to the width of the rectangle making an oblong shaped fishpond.
Length of the rectangle: 2.5 inch
Width of the rectangle and diameter of the circle: 1 inch
1/2 inch equals 15 feet.
2.5 inches = 75 feet
1 inch = 30 feet
Area of a rectangle = 75 ft * 30 ft = 2,250 ft²
Area of a circle = 3.14 * (15ft)² = 3.14 * 225ft² = 706.50 ft²
Total Area = 2,250 ft² + 706.50 ft² = 2,956.50 ft²
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
