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Brrunno [24]
3 years ago
10

A shark is 80 feet below the surface of the water. It swims up and jumps out of the water to a height of 15 feet above the surfa

ce. Find the vertical distance the shark travels.
Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

∆y = 95 ft

the vertical distance the shark travels is 95 ft

Step-by-step explanation:

Given;

Initial position y1= 80 ft below the surface of water = -80ft

Final Position y2 = 15 ft above the surface = +15ft

The vertical distance travelled by the shark is;

∆y = y2 - y1 = 15 - (-80) ft

∆y = 15 +80 ft

∆y = 95 ft

the vertical distance the shark travels is 95 ft

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Answer:

7.3

Step-by-step explanation:

For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.

Distance = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

X2 is 7 (X coordinate of school)

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7 - 5 = 2

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Y1 is 0 (Y coordinate of friend's house)

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Which expression represents the ratio of the difference of the two means to Sidney's mean absolute deviation
prohojiy [21]

Answer:

The ratio of the difference of the two means to Sidney's mean absolute deviation = \frac{4}{3.28} = 1.2195

Step-by-step explanation:

P.S - The exact question is -

Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.

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Mean                                     82                                    78

Mean Absolute Deviation      3.28                                 3.96

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Given, Mean Absolute Deviation of Sydney = 3.28

Now,

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