What is the correct answer?

Three common multiples of 3 and 2

Effectus [21]

Answer:

6, 12, 18

Step-by-step explanation:

3-- 3, 6, 9, 12, 15, 18, 21...

2-- 2, 4, 6, 8, 10, 12, 14, 16, 18, 20...

5 0

3 years ago

2x < 2<br> What is the value of x?

TEA [102]

X can be a value of any number less than 0.9.
Solved, this is x<1 as an inequality.

6 0

2 years ago

What is the quadruple of 2-2

ValentinkaMS [17]

Answer:

Please check the explanation below.

Step-by-step explanation:

As we know that quadruple is basically a fourfold amount or number.

For example,

The quadruple of 6 is 24.

4 x 6 = 24

Similarly, the quadruple of 10 is 40.

4 x 10 = 40

Now, let me solve your query.

Given the expression

2 - 2

as

2-2 = 0

so

we have to determine the quadruple of 0.

i.e.

4 x 0 = 0

Therefore, 0 is the quadruple of 2-2 (or 0).

I hope, it has cleared your concept.

3 0

2 years ago

5-4. Solve each of the following equations for the indicated variable. Use your Equation Mat if it is helpful. Write down each o

balu736 [363]

QUESTION 1

The given equation is :

$2(y - 3) = 4$
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

$\frac{2(y - 3)}{2} = \frac{4}{2}$

We cancel out the common factors to get,

$y - 3 = 2$

We now group like terms to get,

$y = 3 + 2$

We simplify to obtain,

$y = 5$

QUESTION 2

The given equation is

$2x + 5y = 10$
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

$2x= 10 - 5y$

We now divide through by 2, to obtain,

$\frac{2x}{2} = \frac{10}{2} - \frac{5y}{2}$

This will now give us,

$x = 5 - \frac{5}{2} y$

QUESTION 3

The given equation is
$6x + 3y = 4y + 11$

We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

$6x - 11 = 4y - 3y$

We simplify to get,

$6x - 11 = y$

This implies that,

$y = 6x - 11$

QUESTION 4

The given equation is,

$3(2x + 4) = 2 + 6x + 10$

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

$6x + 12 = 2 + 6x + 10$
This implies that

$6x + 12 = 6x + 12$

We group like terms to get,

$6x - 6x = 12 - 12$

We now simplify both sides to get,

$0x = 0$

We don't want x to vanish, so let us try to divide both sides by zero to get,

$x = \frac{0}{0}$

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

$\therefore \: x \in \: R$

QUESTION 5

The given equation is,

$y = - 3x + 6$

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

$y - 6 = - 3x$

We rewrite this to obtain,

$- 3x = y - 6$

We divide through by -3 to get,

$\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}$

This will give us,

$x = - \frac{y}{3} + 2$

or

$x= 2 - \frac{1}{3} y$

5 0

2 years ago

Need help with this problem

Andrei [34K]

All angles of a triangle have to equal 180 degrees. The top and bottom triangle are the same. So the first angle tells you 32 degrees. The second one has a little square which means 90 degrees. So 180 - 32 - 90 = 58.
So the angle A is 58. Since the top triangle and bottom triangle have the same angle measurement then angle C = 58 degrees.

6 0

2 years ago