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gizmo_the_mogwai [7]
3 years ago
11

What is the orbital diagram for fluorine?

Chemistry
1 answer:
pogonyaev3 years ago
8 0

Explanation:

The orbital for fluorine is 1s 2s 2p. All of the boxes should be filled COMPLETELY until you can't no more. How do you know if you can't anymore? By the <u>atomic number</u> of the element. The atomic number for fluorine is 9. So, you keep adding arrows starting from the first box all the way to the last until you have reached the atomic number, in this case, 9.

Answer:

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What is the molar mass of CH20?
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Answer:

30.026 <em>g/mol</em>

Explanation:

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4 0
3 years ago
What is k in the rate law equation?
REY [17]

Answer:

B. A rate constant

Explanation:

The mathematical expression of rate law is given below,

Rate = K[A]m[B]n

This rate law show the relationship between the rate of chemical reaction and concentration of reactants.

In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.

The value of K is specific for particular reaction at particular temperature,

m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature

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3 years ago
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How should students prepare to use chemicals in the lab? Select one or more: Sort the lab chemicals in alphabetical order for qu
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Answer:

Sort the lab chemicals in alphabetical order for quick access.

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Locate the spill kits and understand how they are used.

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7 0
3 years ago
Which of the listed properties are the same for the elements carbon (C), nitrogen (N), and oxygen (O)?
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4 0
3 years ago
1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
Kazeer [188]

1. Answer:

1.0 × 10–9 M OH–

Explanation:

pH = -Log[H+]

pOH = -Log[OH-]

But;

pH + pOH = 14

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Therefore;

[OH-] = 1.0 × 10^-14 M - (1.0 × 10^–5 M)

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2. Answer;

pH = 7.28

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pH = -Log[H3O+]

Given;

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Therefore;

pH = - log [5.2 × 10^–8 M]

     = 7.28

The pH is 7.28

3 0
3 years ago
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