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LiRa [457]
3 years ago
12

An aqueous solution of sodium hydroxide is standardized by titration with a 0.170 M solution of perchloric acid. If 28.5 mL of b

ase are required to neutralize 16.0 mL of the acid, what is the molarity of the sodium hydroxide solution?
Chemistry
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

0.095M

Explanation:

HClO4 + NaOH = NaClO4 + H2O

Concentration of acid CA= 0.170M

Concentration of base CB= ???

Volume of base VB= 28.5ml

Volume of acid VA= 16.0ml

Number of moles of acid nA= 1

Number of moles of base nB= 1

From

CAVA/CBVB= nA/nB

CB= CAVAnB/VBnA

CB= 0.170×16.0×1/28.5×1

CB= 0.095M

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3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:
charle [14.2K]

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

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3 years ago
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7 0
3 years ago
-. You have 100 grams of methane. How many moles do you have?
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Answer:

6.25mol

Explanation:

Using the following formula;

Mole = mass ÷ molar mass

According to this question, there are 100 grams of methane (CH4)

Molar Mass of methane (CH4) = 12 + 1(4)

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mole = 100/16

mole = 6.25moles

Therefore, there are 6.25moles of methane in 100g

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3 years ago
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