Use the periodic table to answer the following questions.

Convert 23.92inHg to torr.

White raven [17]

<h3><u>Answer;</u> </h3>

= 607.568 Torr

<h3><u>Explanation; </u></h3>

1 in of mercury is equivalent to 25.4 Torr

Therefore;

23.92 InHg will be equal to;

23.92 × 25.4

<u>= 607.568 Torr</u>

7 0

3 years ago

Definition: This is a net gain or loss of electrons.

AlekseyPX

Answer:

Elecric charge/ Electricity

Explanation:

Electric charge is the net gain or loss of electrons

I hope im right!!

3 0

3 years ago

1. How many atoms are there in 2.8 moles of carbon? You must show your work to receive credit.

Zolol [24]

Answer:

The answer to your question is

1.- 1.686 x 10²⁴ atoms

2.- 0.25 moles

Explanation:

1.-

1 mol ---------------- 6.023 x 10²³ atoms

2.8 moles ---------- x

x = (2.8 x 6.023 x 10²³) / 1

x = 1.686 x 10²⁴ atoms

2.- 1 mol ------------------ 6.023 x 10 ²³ molecules

x moles ------------- 1.50 x 10²³ molecules

x = (1.50 x 10²³ x 1) / 6.023 x 10²³

x = 0.25 moles

6 0

3 years ago

Read 2 more answers

Who discovered electron ???

Zanzabum

It was a Cambridge UK scientist in the early part of the 20 th century who discovered the electron. His name was J J Thompson.

5 0

3 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m

12345 [234]

<u>Answer:</u> The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For butane:</u>

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol$

<u>For oxygen gas:</u>

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol$

The chemical equation for the reaction of butane and oxygen gas follows:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = $\frac{13}{2}\times 0.224=1.456mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = $\frac{10}{2}\times 0.224=1.12moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

$1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g$

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

8 0

3 years ago