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kifflom [539]
3 years ago
13

A given line has the equation 2x + 12y = −1.

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

i just took the test itsy= (10)x+9y

Step-by-step explanation:


azamat3 years ago
4 0
Y= (10)x+9
Its the answerrrr
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Answer is C:9
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hope it helps
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A high school band has 63 members. 2/9 of the members play a
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Mr. Zillow wants to research the prices in a Subdivision near Disney World called World of Homes. The prices of 14 homes in this
ExtremeBDS [4]

Answer:

Looking for four values or answers

(A) 5.05

(B) 13

(C) $254,140.33

(D) $254,145.38

Step-by-step explanation:

(A) The value of the margin of error.

Using a 90% confidence level or 0.10 alpha level,

1 - alpha = 1 - 0.10 = 0.90

The degrees of freedom = n - 1 = 14 - 1 = 13

Using the t table, 0.90 under 13 is 1.350

Sample size divided by √n is equal to

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1.35 × 3.742 = 5.05

(B) 13 degrees of freedom

(C) To find the lower and upper limits, you find the mean value first and then subtract / add to half of the margin of error which is 5.05÷2 = 2.525

Adding the 14 values together, you have $3,558,000

Dividing by 14 to get the mean;

Mean = $254,142.8571

Lower Limit: $254,140.33

Upper Limit: $254,145.38

4 0
3 years ago
a bonus of 4200 is shared by 10 people who works for a company.40% of the bonus is shared equally between 3 managers the rest of
oee [108]

Step-by-step explanation:

if each the bonus is shared equally each will get 420

if 40% is shared by managers each manager will get 560

if 7 sales persons share 60% each will get 360

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3 years ago
Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

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= e^{0.035\times4}\times4,122.4

= $4,742

8 0
2 years ago
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