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maria [59]
3 years ago
13

The dollar price for a barrel of oil sold at a certain oil refinery tends to follow the demand equation below, where x is the nu

mber of barrels of oil on hand (in millions). ​
(Each question is individual. NOT MULTIPLE CHOICE.)
a) How much should be charged for a barrel of oil if there are 9 million barrels on ​ hand?
​b) What quantity x will maximize​ revenue? ​
c) What price should be charged in order to maximize​ revenue?

p = - 1/10 x + 74
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0
<span>p= -1/10x+74
</span><span>we can write this as
p = -.10x + 74
</span><span>a) How much should be charged for a barrel of oil if there are 9 million barrels on ​ hand?
</span>p = -.10(9) + 74=73.1 a barrel
<span>​b) What quantity x will maximize​ revenue?
</span><span>r(x) = x(-.10x + 74)
r(x) = -.10x^2 + 74x
</span><span>Find the axis of symmetry of this equation x = -b/(2a)
</span>x = -74/(2*(-0.10))=370<span>x = 370 million barrels

</span><span>c) What price should be charged in order to maximize​ revenue?
</span><span>p = -.10(370) + 74
p = -37 + 74
p = $37 a barrel</span>
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3 years ago
A truck can be rented from Company A form ​$130 a day plus $0.30 per mile. Company B charges ​$50 a day plus $0.80 per mile to r
navik [9.2K]

Answer:

160 miles

Step-by-step explanation:

Company A form ​$130 a day plus $0.30 per mile

Company A = 130 + 0.30x

Company B charges ​$50 a day plus $0.80 per mile

Company B = 50 + 0.80x

Where,

x = number of miles

Equate the cost of company A and company B

130 + 0.30x = 50 + 0.80x

Collect like terms

130 - 50 = 0.80x - 0.30x

80 = 0.50x

Divide both sides by 0.50x

x = 80 / 0.50

= 160

x = 160 miles

The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles

4 0
3 years ago
Chris has an account that pays 3.64% simple interest per year and wants to accumulate $3,080 in interest from it over the next 1
Semenov [28]

Answer:

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6 0
3 years ago
What is the solution to the equation x + 14 = 63? (Input a whole number only.) (3 points) Blank 1:
Alex

Hey there!

This is a one-step equation, meaning that we can solve it in one step.

This is the step:

  • Subtract 14 from both sides

Goal:

  • To find out the value of x

Subtract 14:

x+14-14=63-14

the 14's on the left cancel:

x=49

Hence, the answer is

\boxed{\boxed{\bold{x=49}}}

Hope everything is clear.

Let me know if you have any questions!

#LearningDoesn'tEnd

:-)

\rule{200}{2}

7 0
3 years ago
A rectangular box has a square base. The combined length of a side of the square base, and the height is 20 in. Let x be the len
aniked [119]

Answer:

a. V = (20-x) x^{2} in^{3}  

b . 1185.185 in^{3}

Step-by-step explanation:

Given that:

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  • Let x be the length of a side of the base of the box (x>0)

a. Write a polynomial function in factored form modeling the volume V of the box.

As we know that, this is a rectangular box has a square base so the Volume of it is:

V = h *x^{2} in^{3}

<=> V = (20-x) x^{2}  in^{3}

b. What is the maximum possible volume of the box?

To  maximum the volume of it, we need to use first derivative of the volume.

<=> dV / Dx = -3x^{2} + 40x

Let dV / Dx = 0, we have:

-3x^{2} + 40x  = 0

<=> x = 40/3

=>the height h = 20/3

So  the maximum possible volume of the box is:

V = 20/3 * 40/3 *40/3

= 1185.185 in^{3}

7 0
3 years ago
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