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Allisa [31]
3 years ago
12

What are the answers to 18-38

Mathematics
1 answer:
anygoal [31]3 years ago
4 0
The answer to your question is 20
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The math of the PSAT asks multiple choice asks
ExtremeBDS [4]

Answer:

a.More than 3.4 million high school students (mostly juniors and sophomores) take this nationwide, multiple-choice test every year.

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Find the sum of the arithmetic series
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1273

Step-by-step explanation:

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3 years ago
CALC HELP!<br> 16<br> 18<br> 8<br> 32
7nadin3 [17]
I would assume that you would subtract the 2 integrals from each other, the 13 and -3, which will give you 16, and the integral in between 2 to 6, the integral on the right, and then add 2 to 16 which would be 18, I believe that would be the answer.
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3 years ago
What is the intersection of the given lines AE and DE?
cricket20 [7]

Given statement is "What is the intersection of the given lines AE and DE?".

That gives us information that there are two lines named AE and DE which intersect each other. Now we have to find their intersection point.


If you see carefully the name of both lines AE and DE then you will find that; they have common letter "E" in their name.

That means point "E" lies on both lines.

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Which proves that point "E" is the intersection point.


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7 0
2 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
Mariana [72]

Answer:

The questions and problem can be chosen in 1260 ways.

Step-by-step explanation:

Given that, a physics exam consists of 6 open-ended problem and  9 multiple choice questions.

The order of choosing does not matter.

So,we use combination to find ways.

The ways to choose  6 multiple choice from 9 is= ^9C_6

                                                                              =\frac{9!}{6!(9-6)!}

                                                                              =84

The ways to 2 open-ended question from 6  is= ^6C_2

                                                                              =\frac{6!}{2!(6-2)!}

                                                                             =15

Since pick 6 multiple choice out of 9 and 2 open-ended question out of 6 both are independent we have multiply both to find required ways.

Total number of ways is =(84×15)

                                        =1260.

6 0
3 years ago
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