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Contact [7]
3 years ago
13

Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria? Te

mperature ​(°​F) Frequency 40-44 2 45-49 0 50-54 5 55-59 14 60-64 7 65-69 6 70-74 1 Does the frequency distribution appear to have a normal​ distribution?
Mathematics
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

The frequency distribution does NOT appear to have a normal distribution using a strict interpretation of the relevant criteria.

Step-by-step explanation:

Note: See the attached excel file for the Graph of Temperature ​(°​F) vs. Frequency.

A normal distribution refers to a bell-shaped distribution that begins at a low value, grows to a maximum value, and then declines to a low value again. It is a symmetric and a single-peaked distribution.

The fact that the frequency in the data in this question first fell from 2 to 0 before rising again to 5 indicates that it is neither a bell-shaped distribution nor a single-peaked distribution. This is also corroborated by the Graph of Temperature ​(°​F) vs. Frequency in the attached excel file which shows that there are two peaks which are 2 and 14.

Therefore, the frequency distribution does NOT appear to have a normal distribution using a strict interpretation of the relevant criteria.

Download xlsx
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In the rectangle below, E1=2x -2, FH=3x+6, and m 4IHG =35°.Find Gl and m LIEH
Tpy6a [65]

Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

\begin{gathered} FH=2EI, \\ GI=EI. \end{gathered}

Substituting the given expression for each segment in the first equation, we get:

3x+6=2(2x-2).

Solving the above equation for x, we get:

\begin{gathered} 3x+6=4x-4, \\ 3x+6+4=4x, \\ 3x+10=4x, \\ 4x-3x=10, \\ x=10. \end{gathered}

Substituting x=10 in the equation for segment EI, we get:

EI=2*10-2=20-2=18.

Therefore:

GI=18.

Now, to determine the measure of angle IEH, we notice that:

\Delta HFG\cong\Delta GEH,

therefore,

\measuredangle GHF\cong\measuredangle HGE.

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

m\measuredangle IEH=90^{\circ}-35^{\circ}=55^{\circ}.

<h2>Answer: </h2>\begin{gathered} m\operatorname{\measuredangle}IEH=55^{\operatorname{\circ}}, \\ GI=18. \\  \end{gathered}

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1 year ago
Solve the equation. Check your solution. - 6y + 5 = 29y - 2​
mr_godi [17]

Answer:

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Step-by-step explanation:

Simplifying

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Reorder the terms:

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Reorder the terms:

5 + -6y = -2 + 29y

Solving

5 + -6y = -2 + 29y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-29y' to each side of the equation.

5 + -6y + -29y = -2 + 29y + -29y

Combine like terms: -6y + -29y = -35y

5 + -35y = -2 + 29y + -29y

Combine like terms: 29y + -29y = 0

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5 + -5 + -35y = -2 + -5

Combine like terms: 5 + -5 = 0

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-35y = -2 + -5

Combine like terms: -2 + -5 = -7

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Divide each side by '-35'.

y = 0.2

Simplifying

y = 0.2

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