Help me please i need answers for my sisters homework

Mathematics

2 answers:

frozen [14]3 years ago

4 0

Eleven Million Seven Hundred and Sixty Thousand Eight Hundred and Twenty-five.

Mnenie [13.5K]3 years ago

3 0

11,760,825

word form : eleven million seven-hundred sixty thousand eight-hundred twenty- five.

expanded form : 10,000,000 + 1,000,000 + 700,000 + 60,000 + 0 + 800 + 20 + 5

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Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.

wolverine [178]

Answer:

$t_7 =\frac{5}{729}$

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) = $\frac{1}{3}$

The nth term of a geometric sequence is given as:

$t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}$

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3 years ago

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ohaa [14]

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3 years ago

Which expression is equivalent to Assume x > 0 and y 0.

Svetach [21]

we have

$\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}}$

we know that

$\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}} =\sqrt{\frac{55}{11}\frac{x^{7}}{x^{11}}\frac{y^{6}}{y^{8}}} \\ \\= \sqrt{\frac{5}{x^{4} y^{2}}} \\ \\ =\frac{\sqrt{5}}{x^{2} y}$