First, we need to find the missing leg of triangle ACD. We have to use pythagorean theorem to find the missing leg.
a^2 + b^2 = c^2
In this problem,
a = 2
b = ?
c = 5
Plug our numbers into the formula above.
2^2 + b^2 = 5^2
Simplify our terms
4 + b^2 = 25
Subtract 4 from both sides
b^2 = 21
Take the square root of each side
b = √(21)
Now, we can solve for the area of triangle ABC
Area of a triangle = (h * b) / 2
h = height
b = base
In this problem,
h = √(21)
b = 5.0
Plug our numbers into the area formula of a triangle
Area = (√(21) * 5) / 2 = 11.46 square units
Answer:
4 times greater
Step-by-step explanation:
Prism A
SA = 2 (lw+wh+lh) where l is length w is width and h is height
SA = 2 ( 5*6+ 6*7+ 5*7)
SA = 2(30+42+35)
SA = 2(107)
SA =214
Prism B
SA = 2 (lw+wh+lh) where l is length w is width and h is height
SA = 2 ( 10*12+ 12*14+ 10*14)
SA = 2(120+168+140)
SA = 2(428)
SA =856
Robert is not correct
856/214 =4
Prism B is 4 times greater
Answer:
16
Step-by-step explanation:
Given that:
Length of two sides of the triangle = 1 and 16 ;
The largest possible whole-number length of the third side would be ;
Recall from triangle inequality theorem; the length of any two sides of a triangle is greater than the third side. Therefore. The largest possible whole number value the third side could have is:
Assume the third side is the largest :
Then, the third side must be less than the sum of the other two sides ;
Third side < (16 + 1)
Third side < 17
Therefore, the closest whole number lesser than the sum of the other two sides is (17 - 1) = 16
Answer:
The answer is 2.7
Step-by-step explanation:
4.6 - 1.9 = 2.7
