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Temka [501]
3 years ago
6

Solve for , , and . -6x+3y-z=5 3x-y+5z=-10 -x+2y+3z=-1

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

x=1, z=-2, y=3

Step-by-step explanation:

Substitution Method

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How many times greater is 9×10³ than 4×10²
Dima020 [189]

Answer: ^^7 (76-87 x 834 =876*#+9647) - 974 (0 +142 = (8x 17/906385) )

Step-by-step explanation:

you are to nt9 smart to answer this question

5 0
3 years ago
Please help thank you
Elodia [21]

Answer:

a1 = 6

a2 = 15

a3 = 24

a4 = 33

Step-by-step explanation:

Let k =1

a1 =-3 +9(1) = -3 +9 = 6

Let k = 2

a2 = -3 +9(2) =-3+18 = 15

Let k =3

a3 =-3 +9(3) = -3 +27 = 24

Let k = 4

a4 = -3 +9(4) =-3+36 = 33

8 0
4 years ago
Please help and show your work
ElenaW [278]
#6 (you should download an app call “Photomath “)

8 0
3 years ago
Solve the qn in attachment .​
galina1969 [7]

Answer:

\implies \dfrac{ -4x+7}{2(x-2) }

Step-by-step explanation:

The given expression to us is ,

\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}

Now take the LCM as ( x - 1 ) and Simplify , we have ,

\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}

Simplifying further , we get ,

\implies \dfrac{ -4x+7}{2(x-2) }

<u>Hence the second option is correct.</u>

5 0
3 years ago
For question 25 please pick 1,2,3 or 4
Juli2301 [7.4K]

Answer:

4.

$x=\frac{2}{3} \pm  \frac{1}{6}i \sqrt{158}$

Step-by-step explanation:

18x^2-24x+87=0

Using Quadratic Formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-\left(-24\right)\pm \sqrt{\left(-24\right)^2-4\cdot \:18\cdot \:87}}{2\cdot \:18}$

Solving the discriminant:

\Delta = \left(-24\right)^2-4\cdot \:18\cdot \:87\\\Delta = 576-6264\\ \Delta=-5688

$x= \frac{24 \pm \sqrt{-5688} }{36} $

$x= \frac{24 \pm \sqrt{5688i} }{36} $

Once \sqrt{5688} =\sqrt{2^3\cdot \:3^2\cdot \:79}=6\sqrt{158}

$x=\frac{24\pm6\sqrt{158}i}{36}$

Dividing the denominator and numerator by 6

$x=\frac{4\pm \sqrt{158}i}{6}$

Now rewrite it:

$x=\frac{4}{6} \pm  i\frac{\sqrt{158}}{6}$

$x=\frac{2}{3} \pm i \frac{\sqrt{158}}{6}$

or

$x=\frac{2}{3} \pm  \frac{1}{6}i \sqrt{158}$

5 0
3 years ago
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