Answer:
1) you use any parallel lines or rectangles we can double the triangle to get the area and then divide by 2 as we know the length is 92.5yards and we know the width is 53.5 yards.
We would x these by each other and then divide by 2.
We have the width 53 1/2 yards wide and convert this to decimal if we want.
= 53.5 yards.
We then can count the yards for the length = 90 hash marks = 90 yards+ 2.5
= 92.5yards.
We square then add to find the hypotenuse diagonal line but it is an estimate as the lines inscribed subtends into the corner and it becomes a little larger as bottom line is used. Diagonal is found after by doing a reverse equation on the area.
53.5 x 92.5 then divide by 2 = 4948.75/2 = 2474.375
then 2474.375/ 26.75 = 92.5
This proves the line is isosceles and also find the height of the triangle.
But only as an estimate as the actual line distends
Last answer is B and W are equal measures this is because we do not see a right angle and if we bisected the triangle from the goal line to the left side we would prove the midpoint goal line is actually equal and makes lines of play isosceles where two sides are the same at point B and W.
So the answer is 1 yard as B runs the length of the goal back to a position of diagonal run.
The diagonal length is 92.5 yards
Step-by-step explanation:
The mixed number is 4 5/12.
Answer:
1/1080
1/3
y=cos(x/3)
Step-by-step explanation:
just did it
0.1 i guess ok so try my question but im not 100 sure its correct
Answer: [0, 396]
Step-by-step explanation:
The domain is the acceptable values of x in the function. In this case, x = t, the number of tiles. If you think about it, the minimum number of tiles is 0 (you can't have a negative number of tiles), and the maximum number of tiles is 44 (you only have 44 tiles). So, the domain for this function is from 0 to 44.
0 to 44 written in interval notation is [0,44].
The range is the acceptable values of y in the function. In this case, y = A, the area given. A(t) = 9t, so you can use the acceptable values of t to get the range. Again, the minimum area is 0 because you can't have negative area. To find the maximum area, plug in the maximum number of tiles: 9.
A(t) = 9t
A = 9(44)
A = 396
With the maximum number of tiles, 44, the area you get is 396 cm². Therefore, the acceptable values of A are from 0 to 396.
0 to 396 written in interval notation is [0, 396].
