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Darya [45]
3 years ago
8

Please help me out with this questions

Physics
2 answers:
tatuchka [14]3 years ago
8 0
True

Explanation: Since the cornea is a curved surface, it acts like a convex lens and begins to focus the light rays. The light then passes through the pupil and hits the lens of the eye. The lens, also convex, further focuses the light so that it will hit the retina at the back of the eyeball.
Lena [83]3 years ago
4 0

The answer may be true I don't know but, my heart is set on true. Pick what you think it is but my answer is true.

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What happens when the moon faces one side of the earth?
algol [13]
When the moon faces earth a solar eclipse happens :-)
5 0
3 years ago
Which statement is a result of a substance melting. A) The attractions between the particles are stronger. B) The average kineti
Alex73 [517]

the answer is D) on usatestprep

5 0
4 years ago
Read 2 more answers
A 26 cm object is 18 cm in front of a plane mirror. A ray of light strikes the object and is reflected off the mirror at a 42-de
natita [175]
The angle of reflection is the angle between the reflected ray and the normal.
In this case the angle of reflection is 42 degrees

Characteristics of images formed in a plane mirror include
The image is upright
The image is virtual
the image is the same size as the object
The image is at the same distance from the mirror as the object
The image is formed behind the mirror

A plane mirror forms an image which is the same size as the object
Therefore since the object is 26 cm long , the image would still be 26 cm.
4 0
3 years ago
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A 1.20 × 104 kg railroad car moving at 7.70 m/s to the north collides with and sticks to another railroad car of the same mass t
saul85 [17]

Answer: 4.77m/s

Explanation:

According to the law of conservation of momentum which states that the sum total of momentum of bodies before collision is equal to the sum of their momentum after collision. Note that the two bodies will move at a common velocity after colliding.

Let m1 and m2 be the mass of the first and second railroad cars

u1 and u2 be the velocities of the railroad cars

v be the common velocity

Using the formula

m1u1 + m2u2 = (m1 +m2)

m1 = 1.20×10⁴kg

m2 = 1.20×10⁴kg (body of same mass)

u1 = 7.70m/s

u2 = 1.84m/s

v = ?

(1.20×10⁴×7.7) + (1.20×10⁴×1.84) = (1.20×10⁴ + 1.20× 10⁴)v

9.24×10⁴ + 2.21×10⁴ = 2.4×10⁴v

11.45×10⁴ = 2.4×10⁴v

v = 11.45×10⁴/2.4×10⁴

v = 4.77m/s

The velocity of the cars after collision will be 4.77m/s

5 0
3 years ago
A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density
Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

B = \frac{\mu_{0} I}{2R}

Where  B is the magnetic field strength

\mu_{0} is the permeability of free space (\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})

I is the current

and R is the radius

From the give information,

R = 75 \ mm= 75 \times 10^{-3} \ m

and I = 113 \ A

Putting the parameters into the formula, we get

B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }

B = 9.47 \times 10^{-4} \ T

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

u_{B}  = \frac{B^{2} }{2\mu_{0} }

Where u_{B} is the energy density

Then,

u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }

u_{B} = 0.36 \ J/m^{3}

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

7 0
2 years ago
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