Explanation:
As per the problem,

When q > 0 then -q is a negative charge . Since, change in potential energy (
) increases.
or,
> 0
or, 
Therefore, both positive and negative charge will move from
to
and as
so both of them move through a negative potential difference.
Thus, we can conclude that the true statements are as follows.
- The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
- The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
Idk can u say it in a another way