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2 years ago

Acrostic poem for transformation

1 answer:

5 0

An acrostic poem for transformation simply refers to those simple poems conveying transformation messages in which the first letter of each line forms a word or phrase vertically.

A poem can be defined as a a piece of writing in which the expression of feelings and ideas is given intensity by particular attention to diction.

So therefore, an acrostic poem for transformation simply refers to those simple poems conveying transformation messages in which the first letter of each line forms a word or phrase vertically.

Complete question:

What do you understand by acrostic poem for transformation?

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the rover uses 4GHz frequency to transmit the picture. The rover’s transmission power is 200W. The transmission antenna gain is

Gnoma [55]

Answer:

A rover uses 4GHz frequency to transmit a picture. The rover’s transmission power is 200W. Distance = 55*10^9m. The transmission antenna gain is 10,000 and the receiving antenna gain is 100,000. What is the received signal strength at the Earth’s station, in W (assume Pi = 3.14)?

= 31.5 db

Explanation:

Path loss = 20㏒₁₀(4πdf / c)

= 20㏒₁₀(d) + 20㏒₁₀(f) - 20㏒₁₀(4π / c)

= 20㏒₁₀(55 × 10⁹) + 20㏒₁₀(4000) - 147.5

= (20 × 77.4) + 20 × 3.6 - 147.5

= 154 + 72 - 147.5

= 78.5 DB

Received signal strength(power)

Pr = Pt + Gt + Gr - Lp dBW

= 20 + 40 + 50 - 78.5

= 31.5 db

7 0

3 years ago

Find the voltage gain vO/vS and current gain iO/iX for the circuit for g = 0.0025 S. Then, for vS = 4 V, find the power supplied

Lelechka [254]

Answer:

Incomplete question, no circuit diagram.

Check attachment for further explanation and circuit diagram

Explanation:

We want to find Vo/Vs and Io/Ix and also power delivered to the 2 kΩ resistor

Given that,

g= 0.0025 S (i.e conductance )

Vs= 4 V

R1 = 1 kΩ = 1000 Ω

R2 = 3 kΩ = 3000 Ω

R3 = 10 kΩ = 10000 Ω

R4 = 500Ω = 0.5 kΩ

R5 = 2 kΩ = 2000 Ω

a. At Loop 1: let use voltage divider rule to get Vx

Then, Vx = R2/(R1+R2) • Vs

Vx=3/(1+3) •Vs

Vx=¾ Vs.

The small signal current is given as

Is=g•Vx, since Vx=¾Vs

Then, Is= 0.025×¾Vs

Is=3/1600 Vs. Equation 1

Note: Ressistor R4 and R5 are in series, then the equivalent resistance of R4 and R5 is given as

Req= R4+R5

Req=2+0.5=2.5 kΩ

So, using current divider rule between R3 and the equivalent resistance of R4 and R5.

Therefore, Io= R3/(R3+Req) • Is

Io= R3/(R3+Req) • Is equation 2

Note : using ohms law on resistor R5,

V=iR. , R5=2 kΩ

Vo=IoR5

Vo=2Io

Io=Vo/2. Equation 3

Substitute equation 1 and 3 into 2

Io= R3/(R3+Req) • Is

½Vo = 10/(10+2.5) • 3/1600 Vs

½Vo = 10/12.5 • 3/1600 Vs

½Vo = 3/2000 Vs

Vo/Vs = 3/2000 × 2

Vo/Vs = 1 / 1000

The voltage output gain is

Vo/Vs = 1 / 1000

b. From equation 2

Io= R3/(R3+Req) • Is

Also, applying ohms law to resistor R2,

Vx = Ix• R2, R2=3kΩ

Vx = 3•Ix

Given that, Is= g•Vx

Is=0.0025(3•Ix)

Is= 3/400 Ix

Then, Io= R3/(R3+Req) • Is

Io= 10/(10+2.5) • 3/400 Ix

Io= 10/12.5 • 3/400 Ix

Io= 3/500 Ix

Io/Ix= 3/500

The current gain is

Io/Ix= 3/500

c. Output power

Power is given as

P=I²R

Then, output power at Resistor 5 is

Po = Io²•R5

R5=2000 Ω

From loop 1: using KVL, sum of voltage in a loop is zero

-Vs+1000Ix+3000Ix=0

4000Ix=Vs

Since Vs=4

Then, 4000Ix=4

Ix =4/4000

Ix = 1/1000 A

Since, Io/Ix = 3/500

Then, Io = 3/500 • Ix

Io=3/500 × 1/1000

Io= 6×10^-6 A

Therefore,

Po=Io²•R5. ,R5=2000

Po= (6×10^-6l² × 2000

Po=7.2×10^-8 W

Po=72×10^-9 W

Po=72 nW

The output power at resistor R5 is

72 nW

6 0

3 years ago

A certain brand of hot-dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowi

ivanzaharov [21]

Answer:

The time it will take to cook three hot dogs simultaneously is 2.5 minutes

Explanation:

Here we have, the Energy of electric heating given by Joule heating that is;

P = IV = 120×10 = 1200 J/s = 1.2 kJ/s

Since the energy required to cook one hotdog = 60.0 kJ we have

Energy required to cook three hot dogs = 3 × 60.0 kJ = 180.0 kJ

Therefore, the time required to cook the three hot dogs is

(180.0 kJ)/(1.2 kJ/s) = 150 s

The time it takes to cook three hot dogs simultaneously is

150 seconds or 150/60 minutes which is 2 minutes 30 seconds or 2.5 minutes

5 0

3 years ago

Like the alto in a choir the octavina plays the lower melody . what musical element does this tell?

Katena32 [7]

<em>L</em><em>ike the alto in a choir the octavina plays the lower melody . what musical element does this tell?</em>

answer : melody....

7 0

3 years ago

The lawn sprinkler consists of four arms that rotate in the horizontal plane. The diameter of each nozzle is 8 mm, and the water

sashaice [31]

Answer: the constant angular velocity of the arms is 86.1883 rad/sec

Explanation:

First we calculate the linear velocity of the single sprinkler;

Area of the nozzle = π/4 × d²

given that d = 8mm = 8 × 10⁻³

Area of the nozzle = π/4 × (8 × 10⁻³)²

A = 5.024 × 10⁻⁵ m²

Now total discharge is dived into 4 jets so discharge for single jet will be;

Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec

So using continuity equation ;

Q_single = A × V_single

V_single = Q_single/A

we substitute

V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)

V_single = 29.8566 m/s

Now resolving the forces as shown in the second image,

Vt = Vcos30°

Vt = 29.8566 × cos30°

Vt = 25.8565 m/s

Finally we calculate the angular velocity;

Vt = rω

ω_single = Vt / r

from the given diagram, radius is 300mm = 0.3m

so we substitute

ω_single = 25.8565 / 0.3

ω_single = 86.1883 rad/sec

Therefore the constant angular velocity of the arms is 86.1883 rad/sec

7 0

3 years ago