According to Newton's Second Law of Motion :
The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.
Force acting = Mass of the Object × Acceleration
Given : Force = 50 newton and Mass of the Object = 10 kg
Substituting the respective values in the Formula, we get :
50 N = 10 kg × Acceleration

Acceleration of the Object = 5 m/s²
M=2.45 because you multiply out the equation on the right and divide by 10
Answer:
The magnitude of the torque is 263.5 N.
Explanation:
Given that,
Applied force = 31 N
Distance from the axis = 8.5 m
She applies her force perpendicularly to a line drawn from the axis of rotation
So, The angle is 90°
We need to calculate the torque
Using formula of torque

Where, F = force
d = distance
Put the value into the formula
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
Hence, The magnitude of the torque is 263.5 N.
Answer:
20 watts
Explanation:
Big brain mode activated:
Power=1200J/60sec
Power=20 watts
Answer:
Explanation:
Given that, the pilot can withstand 9g acceleration which is approximately 88m/s².
Now, the pilot is traveling in a circle of radius
r = 3340 m
And the speed is
v = 495 m/s
Then, acceleration?
The acceleration of a circular motion can be determine using centripetal acceleration
a = v² / r
a = 495² / 3340
a = 73.36 m/s².
Since the acceleration is less that the acceleration the pilot can withstand, then, I think the pilot makes the turn without blacking out and successfully