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zzz [600]
3 years ago
13

16. For quadrilateral ABCD, determine the most precise name for it. A(2,3), B (12,3), C(8,6) and D(5,6). Show your work and expl

ain.
Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0
The answer will be , It is a trapezoid
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Please help asap!! 50 points!!!!!!
kicyunya [14]

Answer:

1

Step-by-step explanation:

{5x}^{4}  +  {7x}^{3}   - 2  {x}^{2}  - 3x + c \div (x + 1) \\  = (5 {x}^{3} + 2 {x}^{2}   - 4x + 1)(x + 1) + c - 1 \\  \\ c - 1 = 0 \\ c = 1

6 0
3 years ago
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Which expression represents the area of the triangle drawn below (4x-3) (2x-1) (4x-2) (3x-3)?
nata0808 [166]

Answer:

option C

Step-by-step explanation:

Area of the triangle=4x²+4x+1

6 0
3 years ago
Find the dimensions of the rectangle with largest area that can be inscribed in an equilateral triangle with sides of 1 unit, if
prohojiy [21]
<span>Maximum area = sqrt(3)/8 Let's first express the width of the triangle as a function of it's height. If you draw an equilateral triangle, then a rectangle using one of the triangles edges as the base, you'll see that there's 4 regions created. They are the rectangle, a smaller equilateral triangle above the rectangle, and 2 right triangles with one leg being the height of the rectangle and the other 2 angles being 30 and 60 degrees. Let's call the short leg of that triangle b. And that makes the width of the rectangle equal to 1 minus twice b. So we have w = 1 - 2b b = h/sqrt(3) So w = 1 - 2*h/sqrt(3) The area of the rectangle is A = hw A = h(1 - 2*h/sqrt(3)) A = h*1 - h*2*h/sqrt(3) A = h - 2h^2/sqrt(3) We now have a quadratic equation where A = -2/sqrt(3), b = 1, and c=0. We can solve the problem by using a bit of calculus and calculating the first derivative, then solving for 0. But since this is a simple quadratic, we could also take advantage that a parabola is symmetrical and that the maximum value will be the midpoint between it's roots. So let's use the quadratic formula and solve it that way. The 2 roots are 0, and 1.5/sqrt(3). The midpoint is (0 + 1.5/sqrt(3))/2 = 1.5/sqrt(3) / 2 = 0.75/sqrt(3) So the desired height is 0.75/sqrt(3). Now let's calculate the width: w = 1 - 2*h/sqrt(3) w = 1 - 2* 0.75/sqrt(3) /sqrt(3) w = 1 - 2* 0.75/3 w = 1 - 1.5/3 w = 1 - 0.5 w = 0.5 The area is A = hw A = 0.75/sqrt(3) * 0.5 A = 0.375/sqrt(3) Now as I said earlier, we could use the first derivative. Let's do that as well and see what happens. A = h - 2h^2/sqrt(3) A' = 1h^0 - 4h/sqrt(3) A' = 1 - 4h/sqrt(3) Now solve for 0. A' = 1 - 4h/sqrt(3) 0 = 1 - 4h/sqrt(3) 4h/sqrt(3) = 1 4h = sqrt(3) h = sqrt(3)/4 w = 1 - 2*(sqrt(3)/4)/sqrt(3) w = 1 - 2/4 w = 1 -1/2 w = 1/2 A = wh A = 1/2 * sqrt(3)/4 A = sqrt(3)/8 And the other method got us 0.375/sqrt(3). Are they the same? Let's see. 0.375/sqrt(3) Multiply top and bottom by sqrt(3) 0.375*sqrt(3)/3 Multiply top and bottom by 8 3*sqrt(3)/24 Divide top and bottom by 3 sqrt(3)/8 Yep, they're the same. And since sqrt(3)/8 looks so much nicer than 0.375/sqrt(3), let's use that as the answer.</span>
7 0
3 years ago
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Y+5=2(x+1)<br><br><br> what is the slope for this Math
Stells [14]

Answer:

2

Step-by-step explanation:

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.y=mx+bRewrite in slope-intercept form.Simplify 2(x+1).Apply the distributive property.

y+5=2x+2⋅1

multiply 2 by 1.

y+5=2x+2

y+5=2x+2

Move all terms not containing y to the right side of the equation.Subtract 5 from both sides of the equation.

y=2x+2−5

y=2x−3

the slope is the "m" so the slope is 2

7 0
3 years ago
Consider the equation: x^2-51=14x Rewrite the equation by completing the square and what the solution to the equation​.
Mariana [72]

Answer:

x = -3 and x = 17

Step-by-step explanation:

x² - 51 = 14x

x² - 14x - 51 = 0

(x + 3)(x - 17) = 0

x = -3 and x = 17

4 0
3 years ago
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