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notsponge [240]
3 years ago
6

name the theorem or postulate that lets you conclude triangle ABD is congruent to triangle CBD with only one additional step

Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Answer:

The answer is the first one ⇒ AAS

Step-by-step explanation:

∵ DB ⊥ AC

∴ m∠DBA = m∠DBC = 90° ⇒ (1)

∵ m∠A = m∠C ⇒ (2) given (from figure)

∵ DB is a common side in the two Δ ⇒ (3)

From (1) , (2) and (3)

∴ Δ ABD is congruent to Δ CBD ⇒ AAS

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Answer:

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Step-by-step explanation:

We assume the storage room is a rectangle, like most rooms, no indication it is otherwise.

We know it's a rectangle and not a square because it is longer than wide.

We have the perimeter measurement (16 meters).

So, we can make the following equation:

2x + 2y = 16

x being the width of the room, y being it's length.  A perimeter is the sum of all sides.

We also know the room is 2 meters longer than wide... so:

y = x + 2

If we replace y in the first equation by its value relative to x, we get:

2x + 2(x + 2) = 16 which becomes

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Width: 3 meters

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3 years ago
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Sladkaya [172]

Answer:

D

Step-by-step explanation:

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