Question

In ∆ABC with m∠C = 90° the sides satisfy the ratio BC:AC:AB = 4:3:5. If the side with middle length is 12 cm, find: 1) The perimeter of ∆ABC; 2) The area of ∆ABC; 3) The height to the hypotenuse.
Please walk me through the question. 20 points.

Answer 1

First of all, let's find the dimensions of your triangle. The middle length of the ratio is 4, so the scale factor is (12 cm)/4 = 3 cm. Thus the other two side lengths are 3×3 cm = 9 cm, and 5×3 cm = 15 cm.

The area of a triangle is the same no matter how you compute it. If you compute it using the legs of the right triangle, you find it is
  A = (1/2)×(12 cm)×(9 cm) = 54 cm²

If you compute it using the hypotenuse and the height to the hypotenuse, it is the same.
  A = 54 cm² = (1/2)×(15 cm)×height
We solve this for height by dividing by the coefficient of height. Doing so, we find
  height = (54 cm²)/(7.5 cm) = 7.2 cm

The height to the hypotenuse is 7.2 cm.