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Ainat [17]
3 years ago
12

Which region represents the solution to the given system of inequalities?​

Mathematics
2 answers:
TEA [102]3 years ago
7 0

The first equation shows C and D, and the second shows C and B. The overlap will be at C, so thats the answer.

Gnoma [55]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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3x + y = 23<br> 3x - 2y = 8
sergey [27]

Answer:

5

Step-by-step explanation:

difference in y is 3

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3 years ago
Natalie had a job after school. She worked 25 hours a week and got paid $6.25 an hour. How much money would she earn for two wee
erastovalidia [21]

Answer:

312.5

Step-by-step explanation:

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kykrilka [37]

Using the Euler's formula, the number of segments in the pentagonal prism is: 15.

<h3>What is the Euler's Formula?</h3>

The Euler's formula is given as,  F + V = E + 2, where:

  • F = number of faces (number of regions)
  • V = vertices
  • E = number of edges (number of segments).

Given that the pentagonal prism has the following dimensions:

  • F = 7
  • V = 10
  • E = number of segments = ?

Plug in the values into the Euler's formula, F + V = E + 2:

7 + 10 = E + 2

17 - 2 = E

E = 15

Therefore, using the Euler's formula, the number of segments in the pentagonal prism is: 15.

Learn more about the Euler's formula on:

brainly.com/question/1178790

5 0
2 years ago
A baker has 10 cups of sugar to make cookies. Each batch calls for 1 1/3 cups of sugar.
disa [49]
\bf \textit{he can make }10\div 1\frac{1}{3}\qquad or\qquad \cfrac{10}{1\frac{1}{3}}&#10;\\\\\\&#10;1\frac{1}{3}\implies \cfrac{1\cdot 3+1}{3}\implies \cfrac{4}{3}\\\\&#10;-----------------------------\\\\&#10;\cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\qquad thus\\\\&#10;-----------------------------\\\\

\bf \cfrac{10}{\frac{4}{3}}\implies \cfrac{\frac{10}{1}}{\frac{4}{3}}\implies \cfrac{10}{1}\cdot \cfrac{3}{4}\implies \cfrac{30}{4}\implies \cfrac{15}{2}\implies \boxed{7\frac{1}{2}}&#10;\\\\\\&#10;because\implies \cfrac{7\cdot 2+1}{2}\implies \cfrac{15}{2}
6 0
3 years ago
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