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2 years ago

Classify the following triangle. Check all that apply.

Mathematics

1 answer:

V125BC [204]2 years ago

4 0

Acute < 90
Right = 90
Obtuse > 90
This triangle is 104 degree so it is obtuse.

Isosceles = 2 same size
Scalene = no same size
Equilateral = all same size
You can see their is mark on 2 sides so it would be isosceles

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docker41 [41]

Answer:

Both answers are 3.

Step-by-step explanation:

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3 years ago

The volume of a cone is 16x cubic inches, Its height is 12 inches. What is the radius of the cone?

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3 years ago

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(21)

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(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

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(24)

Given is the inradius of an equilateral triangle.

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Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

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2 years ago

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Gennadij [26K]

Answer:

-3/5

Step-by-step explanation:

to figure that out you have to do y^2 - y^1/ x^2 - x^1

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2 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

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And if we replace the value given we got:

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For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

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2 years ago