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4 years ago

How do you find 33% of $84?

Mathematics

2 answers:

My name is Ann [436]4 years ago

8 0

33% = 0.33

'of' indicates multiplication

0.33 * 84 = 27.72

So $27.72

BartSMP [9]4 years ago

8 0

When you are finding % of $ you do this:
33%=$84
(= means of)
84*33=$27.72
so.. 33% of $84 is $27.72
Hope I helped! :P

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5x−y=14 in slope intercept form y=_

frozen [14]

Simple, rewrite this equation, in y=mx+b form.

Move over the 5x, making it look like, -y=-5x+14

Then, just simply divide by the negative one in front of the y.

y=5x-14.

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3 years ago

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Nerissa paid a total of $8 for 4 packs of pencils she purchased from the convenience store. Let p represent the cost of one pack

BARSIC [14]

Answer: 4*p=8

Step-by-step explanation:

You can use inverse operation to answer this equation.

write out you problem: 4 x p =8
The inverse of multiplication is division
you do 4/4 which gives you one but the 4 will cancel itself out
Do 8/4 which gives you 2
under the equation write p = 2
And be sure to line the p up with the p, the equal sign with the equal sign, and the 2 stays where it is ( which should be already lined up with the 8)

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3 years ago

I’m so confused someone please help me

asambeis [7]

Answer:

Figure 5

Step-by-step explanation:

Figure 5, if you draw a line down the middle it is the same on both sides

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3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

4 years ago

5/6=x-10/3x+6 solution?

Ivan

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{x = - 10}}}}}$