#1: 214 tickets split 9 ways does not work out to an integer number. Nobody wants 2/3 of a ticket, right?
So the trick here is to determine the first multiple of 9 greater than 214.
Note that 214/9 = 23.8. No good. Not an integer.
Multiply 23 by 9; we get 207. Multiply 24 by 9; we get 216.
So, given that we have 214 tickets already, we need 2 more, to make 216.
Check: Is 216 divisible by 9 without a remainder? Yes. Then each of the 9 students will get 24 tickets.
The rest of the problems are somewhat similar to this one.
See whether you can do the next one, #2.
If you'd share your results, I'd be happy to comment on what you've done.
Answer:
Infinite number of solutions.
Step-by-step explanation:
Y=5x+1
-5x+Y=1
substitute value of y in first equation (5x+1) into 2nd equation
-5x+5x+1=1
0+1=1
1=1
since answer equals on both sides of the equatio, the answer is determined to be infinite.
Answer:
16 fits but not evenly
Step-by-step explanation:
16 times 3 equals 48 and 17 times 3 equal is 51 so someone didnt go 3 times.
y=6x-3
put a point on (0,-3) this is your y intercept
go up 6 and over 1 this should land you at (1,0) do this again and your at (2,6)
go back to the y intercept now go down 6 and over 1, this should land you (-1,-6)
continue to do this until you graph is filled
Answer:
= 4
Step-by-step explanation:
sqrt 15 = 3.872
to approximate to the nearest whole number (integer), you take the first decimal number which is 8, since 8 is greater than 5, you will add one(1) to the whole number which is 3 to make it 4.
