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Nana76 [90]
3 years ago
7

42x(raise to 4) - 13x² - 40

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0
I hope this helps you

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What is 8 divided by 2(2+2)=16
LuckyWell [14K]

Answer:

answer is sixteen (16)

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The diagram shows a 3 cm x 5 cm x 4 cm cuboid
Rainbow [258]

Answer:

a) The length of segment AC is approximately 5.83 centimeters.

b) The angle ACD is approximately 34.5º.

Step-by-step explanation:

a) Since AB \perp BC, the length of segment AC is determined by Pythagorean Theorem, that is:

AC = \sqrt{(5\,cm)^{2}+(3\,cm)^{2}}

AC \approx 5.831\,cm

The length of segment AC is approximately 5.831 centimeters.

b) Since AB \perp BC \perp AD, the length of segment AD is determined by this Pythagorean identity:

AD = \sqrt{(3\,cm)^{2}+(5\,cm)^{2}+(4\,cm)^{2}}

AD \approx 7.071\,cm

The angle ACD is determined by the following trigonometric expression:

\cos C = \frac{AC}{CD}

\cos C = \frac{5.831\,cm}{7.071\,cm}

\cos C = 0.825

C = \cos^{-1} 0.825

C \approx 34.448^{\circ}

The angle ACD is approximately 34.448º.

4 0
2 years ago
Plz help me fast Simplify t12/t6
Digiron [165]

Answer:

t^6

Step-by-step explanation:

when dividing exponents, you subtract (refer to exponent rule)

t^12 - t^6 = t^6

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2 years ago
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Jamie says that if she knows only the measure of one angle in an isosceles triangle, she can always determine the measures of th
lozanna [386]

Answer:

Jamie is correct

Step-by-step explanation:

Jamie is correct.

Example: isosceles triangle ABC AB=AC

∠B = ∠C        ∠A + ∠B + ∠C = 180°

if ∠A = x     ∠B = ∠C = 1/2 * ( 180° - x)

if ∠B or ∠C = x            ∠A = 180° - 2x

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3 years ago
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An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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