Answer:
solution set are
Step-by-step explanation:
we are given system of equation as
For finding solution set , we can draw graph of both equations
and then we can find intersection point
the intersection point will be our solution set
we get graph as
So, solution set are
8.85 x 1000= 8,850
Hoped this helped.
~Bob Ross®
If AB is 6 and AC is 4. Look at how BC it longer than AC but shorter than AB. The number in between would be 5 so the answer is 5cm.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Reading a coordinate plane
- Coordinates (x, y)
- Slope Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point (-4, -4)
Point (-2, 2)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute in points [Slope Formula]:
- [Fraction] Subtract:
- [Fraction] Divide:
Answer:
- 891 = 3^4 · 11
- 23 = 23
- 504 = 2^3 · 3^2 · 7
- 230 = 2 · 5 · 23
Step-by-step explanation:
23 is a prime number. That fact informs the factorization of 23 and 230.
The sums of digits of the other two numbers are multiples of 9, so each is divisible by 9 = 3^2. Dividing 9 from each number puts the result in the range where your familiarity with multiplication tables comes into play.
891 = 9 · 99 = 9 · 9 · 11 = 3^4 · 11
___
504 = 9 · 56 = 9 · 8 · 7 = 2^3 · 3^2 · 7
___
230 = 10 · 23 = 2 · 5 · 23
_____
<em>Comment on divisibility rules</em>
Perhaps the easiest divisibility rule to remember is that a number is divisible by 9 if the sum of its digits is divisible by 9. That is also true for 3: if the sum of digits is divisible by 3, the number is divisible by 3. Another divisibility rule fall out from these: if an even number is divisible by 3, it is also divisible by 6. Of course any number ending in 0 or 5 is divisible by 5, and any number ending in 0 is divisible by 10.
Since 2, 3, and 5 are the first three primes, these rules can go a ways toward prime factorization if any of these primes are factors. That is, it can be helpful to remember these divisibility rules.
