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ASHA 777 [7]
3 years ago
11

I need help please help me now please

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
8 0
The answer is C, balanced
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Write a balanced overall reaction from these unbalanced half-reactions sn and ag
loris [4]
Balance each one by adding electrons to make the charges on both sides the same:

Sn--> Sn2+ + 2 e-
Ag+ + 1 e- --> Ag

Now, you have to have the same number of electrons in the two half-reactions, so multiply the second one by 2 to get:

2 Ag+ + 2 e- --> 2 Ag

Now, just add the two half reactions together, cancelling anything that's the same on both sides:

2 Ag+ + Sn --> Sn2+ + 2 Ag

And you're done.
8 0
3 years ago
Identifying Qualitative and quantitative Data
lyudmila [28]

Answer:

qualitative data :           quantitative data :      

circular in shape            75 colonies ...          

stained purple               200 purple ..

spreads across plate    55 colonies ...          

Explanation:

i got it right :) .

7 0
3 years ago
The Hall process for the production of aluminum involves the reaction of aluminum oxide with elemental carbon to give aluminum m
topjm [15]

Answer:

  • <u><em>1.7 × 10³ kg of ore.</em></u>

Explanation:

Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.

Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:

  •  X         ×          71%                ×       82%     =     1.0 × 10³ kg

         ↑                      ↑                              ↑                     ↑

(mass of ore)    (% of Al in the ore)        (yield)        ( Al metal to obtain)

You must just simplify, solve and compute:

  • 0.71 × 0.82 × X = 1,000
  • X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg

Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.

6 0
3 years ago
Read 2 more answers
Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. if 100 grams of hydrochloric acid reacts with 100 g
natita [175]
The balanced chemical reaction is:

2HCl + Ca = CaCl2 + H2

We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

100 g HCl ( 1 mol HCl / 36.46 g HCl ) = 2.74 mol HCl

100 g Ca ( 1 mol Ca / 40.08 g ) = 2.08 mol Ca

From the reaction, the mole ratio of the reactants is 2:1 where every 2 moles of hydrochloric acid, 1 mole of calcium is required. Therefore, the limiting reactant for this case is calcium.
4 0
3 years ago
Read 2 more answers
The answer to question 2
Bad White [126]

Answer:


12


Explanation:


You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.


M_{r}:                           258.21       18.02


                 KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O


Mass/g:             4.74                                       2.16


Step 1. Calculate the mass of the KAl(SO₄)₂.


Mass = 4.74 g – 2.16 g = 2.58 g.


Step 2. Calculate the moles of each product.


\text{Moles of KAl(SO}_{4})_{2} = \text{2.58 g} \times \frac{\text{1 mol} }{\text{258.21 g}} = 9.992 \times 10^{-3} \text{ mol}

\text{Moles of H}_{2}\text{O} = \text{2.16 g} \times \frac{\text{1 mol} }{\text{18.02 g}} = \text{ 0.1200 mol}

Step 3. Calculate the molar ratio of the two products.


\frac{\text{Moles of KAl(SO}_{4})_{2}}{\text{Moles of H}_{2}\text{O}} = \frac{ 9.992 \times 10^{-3} \text{ mol}}{\text{ 0.1200 mol} } = \frac{1 }{12.01} \approx \frac{ 1}{ 12}

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.



3 0
4 years ago
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